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sergejj [24]
3 years ago
5

Express (2-I) - (-1+3i) in the form of a + ib.

Mathematics
2 answers:
oksian1 [2.3K]3 years ago
7 0

Answer:

=3-4i

Step-by-step explanation:

So we have:

(2-i)-(-1+3i)

First, distribute:

=(2-i)+1-3i

Combine like terms:

=-i-3i+2+1

Add:

=-4i+3

So, in the a+bi format, we will have:

=3-4i

BartSMP [9]3 years ago
6 0

Answer:

3 -4i

Step-by-step explanation:

(2-i) - (-1+3i)

Distribute the minus sign

(2-i) + 1-3i

Combine like terms

3 -4i

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Answer:

1. All real numbers

2. All real numbers except y = 0

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4. All real numbers except b = 10

Step-by-step explanation:

For any function to be defined at a particular value, it should not be <em>approaching to a value </em>\infty<em> or it should not give us the </em>\frac{0}{0}<em> (zero by zero) form </em> when the input is given to the function.

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Now, let us consider the given functions one by one:

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At y = 0, the value

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So, the given function is <em>defined for all real numbers except y = 0</em>

<em></em>

<em></em>3.\ \dfrac{1}{x+7}<em></em>

Let us consider denominator:

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<em></em>

4.\ \dfrac{2b}{10-b}

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10-b can be zero at a value b = 10

At\ b =10,  \dfrac{2b}{10-b} \rightarrow \infty

So, the given function is <em>defined for all real numbers except b = 10</em>

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Answer:

  see attached

Step-by-step explanation:

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The graph of g(x) is attached.

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