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Ket [755]
3 years ago
12

PLS HELP ME ITS DUE AT 12 AM I WILL GIVE THAT BRAINLY THING

Mathematics
1 answer:
Eduardwww [97]3 years ago
4 0

9514 1404 393

Answer:

  1. HA is equivalent to AAS when the triangle is a right triangle.

  2. AM = BM, so the triangles are congruent by HL. CPCTC

  3. The triangles are congruent by HL. CPCTC

Step-by-step explanation:

1. The acute angle of the triangle together with the right angle comprise two angles of the triangle. When two corresponding angles and a corresponding side (the side opposite the right angle) are congruent, the right triangles are congruent by the AAS theorem. (This can be referred to as the HA theorem.)

__

2. CM = DM; MA = MB; ∠A = ∠C = 90°, so all of the requirements for the HL theorem are met. ΔCMA ≅ ΔDMB, so AC ≅ BD by CPCTC.

__

3. TS = TV, TR = TR, ∠S = ∠V = 90°, so all requirements for the HL theorem are met. ΔTSR ≅ ΔTVR, so RS ≅ RV by CPCTC.

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(79,35+7,32) × 42,2-9543​
vladimir2022 [97]

Answer:

42(79,42,32)

Step-by-step explanation:

I got the solution by using  the  Trigonometric Identities. If somebody else could do a step by step explanation that would be great.  

3 0
2 years ago
A regular hexagon has a perimeter of 72 feet. How long is each side?
Lena [83]

Step-by-step explanation:

a hexagon has 6 sides

so it's only 72/6

so each side is <u>1</u><u>2</u><u>f</u><u>t</u>

7 0
3 years ago
Read 2 more answers
If f(1) =7 and f(n)=-5f(n-1)-n<br><br> then find the value of <br> f(4)
jolli1 [7]

Answer:

-914

Step-by-step explanation:

f(n)=-5f(n-1)-n

f(2)= -5f(1) -2 = -5(7) - 2 = -37

f(3) = -5f(2) - 3 = -5(-37) - 3 = 182

f(4) = -5f(3) - 4 = -5(182) - 4 = -914

4 0
3 years ago
Evaluate the following integral using trigonometric substitution
serg [7]

Answer:

The result of the integral is:

\arcsin{(\frac{x}{3})} + C

Step-by-step explanation:

We are given the following integral:

\int \frac{dx}{\sqrt{9-x^2}}

Trigonometric substitution:

We have the term in the following format: a^2 - x^2, in which a = 3.

In this case, the substitution is given by:

x = a\sin{\theta}

So

dx = a\cos{\theta}d\theta

In this question:

a = 3

x = 3\sin{\theta}

dx = 3\cos{\theta}d\theta

So

\int \frac{3\cos{\theta}d\theta}{\sqrt{9-(3\sin{\theta})^2}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9 - 9\sin^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{\theta})}}

We have the following trigonometric identity:

\sin^{2}{\theta} + \cos^{2}{\theta} = 1

So

1 - \sin^{2}{\theta} = \cos^{2}{\theta}

Replacing into the integral:

\int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{2}{\theta})}} = \int{\frac{3\cos{\theta}d\theta}{\sqrt{9\cos^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{3\cos{\theta}} = \int d\theta = \theta + C

Coming back to x:

We have that:

x = 3\sin{\theta}

So

\sin{\theta} = \frac{x}{3}

Applying the arcsine(inverse sine) function to both sides, we get that:

\theta = \arcsin{(\frac{x}{3})}

The result of the integral is:

\arcsin{(\frac{x}{3})} + C

8 0
3 years ago
Please help me thank you so much
HACTEHA [7]
I think the answer is 15
5 0
2 years ago
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