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vovikov84 [41]
3 years ago
14

There are nine cheerleaders how many different arrangements can the cheerleaders march one behind the other

Mathematics
1 answer:
babymother [125]3 years ago
3 0
<h3>Answer:  362,880</h3>

note: this is one single number. The comma helps make it more readable

=============================================

Explanation:

We have 9 positions to fill. The first position has 9 choices, the second has 8 (since we cannot pick the same person twice), then 7, then 6, and so on until we count down to 1. We multiply out all these values mentioned.

9*8*7*6*5*4*3*2*1 = 362,880

The idea of multiplying whole numbers counting down to 1 is a concept known as factorials. Because order matters, the value 362,880 represents the number of permutations possible.

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15 divided by 4 is 3.75. Please mark brainliest

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0

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What is the relationship between the lines determined by the following two equations?
oksano4ka [1.4K]

Answer:

C. They are the same line.

Step-by-step explanation:

In order to compare the linear equations given, they need to be in the same form.  The best form in order to evaluate slope and y-intercept is slope-intercept form, y = mx + b.  Since the second equation is already in slope-intercept form, we need to use inverse operations to convert the first equation:

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4 0
3 years ago
The set of the consecutive odd numbers 1, 3, 5, 7, ... , N has a sum of 400. How many numbers are in the set?
Amanda [17]

Well, we could try adding up odd numbers, and look to see when we reach 400. But I'm hoping to find an easier way.

First of all ... I'm not sure this will help, but let's stop and notice it anyway ...
An odd number of odd numbers (like 1, 3, 5) add up to an odd number, but
an even number of odd numbers (like 1,3,5,7) add up to an even number.
So if the sum is going to be exactly 400, then there will have to be an even
number of items in the set.

Now, let's put down an even number of odd numbers to work with,and see
what we can notice about them:

         1, 3, 5, 7, 9, 11, 13, 15 .

Number of items in the set . . . 8
Sum of all the items in the set . . . 64

Hmmm.  That's interesting.  64 happens to be the square of 8 . 
Do you think that might be all there is to it ?

Let's check it out:

Even-numbered lists of odd numbers:

1, 3                                   Items = 2, Sum = 4
1, 3, 5, 7                           Items = 4, Sum = 16
1, 3, 5, 7, 9, 11                 Items = 6, Sum = 36
1, 3, 5, 7, 9, 11, 13, 15 . . Items = 8, Sum = 64 .

Amazing !  The sum is always the square of the number of items in the set !

For a sum of 400 ... which just happens to be the square of 20,
we just need the <em><u>first 20 consecutive odd numbers</u></em>.

I slogged through it on my calculator, and it's true.

I never knew this before.  It seems to be something valuable
to keep in my tool-box (and cherish always).


3 0
3 years ago
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