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3 years ago

There are nine cheerleaders how many different arrangements can the cheerleaders march one behind the other

Mathematics

1 answer:

babymother [125]3 years ago

3 0

<h3>Answer: 362,880</h3>

note: this is one single number. The comma helps make it more readable

=============================================

Explanation:

We have 9 positions to fill. The first position has 9 choices, the second has 8 (since we cannot pick the same person twice), then 7, then 6, and so on until we count down to 1. We multiply out all these values mentioned.

9*8*7*6*5*4*3*2*1 = 362,880

The idea of multiplying whole numbers counting down to 1 is a concept known as factorials. Because order matters, the value 362,880 represents the number of permutations possible.

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Simplify each expression 25 × 3 + 60 × 2

AveGali [126]

first you would multiply 25 x 3, which is 75 and then multiply 60 x 2 which is 120, then add 120 and 75 together, making the answer 195

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3 years ago

Suppose the six people consist of three mar- ried couples and each couple wants to sit together with the older partner on the le

chubhunter [2.5K]

6 possible ways to order 3 couples in a row

Given,

We have three married couples. that is six persons in total.

a, b, c, d, e, f may taken as the six persons.

Considering the statement:

Elder partner on the left, assume a, c and e as elders.

Then we have, (a, b) ------ ( 1)

(c, d) ------ (2)

(e, f) ------ (3)

There is no change in position between the couples.

So, we get three persons in total.

Possible ways to order these three persons will be like this: 3! = 3×2×1

= 6

Learn more about seating arrangement here ; brainly.com/question/10702719

#SPJ4

4 0

2 years ago

Help anyone plezzzzzzzzzzzzzzzzzzz

emmainna [20.7K]

<span> Direct-substituting x = -2 gives 0/0, so we know that by the factor theorem, both the numerator and denominator have a factor of x + 2. From there, we can cancel out the conflicting factors and apply the limit.

We can factor the numerator and denominator to get:

x^3 - x^2 - x + 10 = (x + 2)(x^2 - 3x + 5)
x^2 + 3x + 2 = (x + 2)(x + 1).

So we have:

lim (x-->-2) (x^3 - x^2 - x + 10)/(x^2 + 3x + 2)
= lim (x-->-2) [(x + 2)(x^2 - 3x + 5)]/[(x + 2)(x + 1)]
= lim (x-->-2) (x^2 - 3x + 5)/(x + 1), by canceling out x + 2
= [2^2 - 3(-2) + 5]/(-2 + 1)
= (4 + 6 + 5)/(-1)
= -15.

I hope this helps! </span>

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3 years ago

The sum of 3 consecutive even numbers is 60. What are they?

ASHA 777 [7]

Answer:

18, 20 and 22.

Step-by-step explanation:

Let the lowest number be n, then:

n + n + 2 + n + 4 = 60

3n + 6 = 60

3n = 54

n = 18.

So the other 2 are 20 and 22.

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1 year ago

Circle P is shown. Line segment A B goes from one side of the circle to another. Line segment E F is a tangent that intersects t

Harrizon [31]

Answer:81

Step-by-step explanation:

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3 years ago

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