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cestrela7 [59]
3 years ago
11

How do you solve - (4n + 5y + 6)

Mathematics
1 answer:
slamgirl [31]3 years ago
4 0

Answer:

-4n + 5y + 6

Step-by-step explanation:

Distribute the negative

−4n + 5y + 6

There is really no answer for this but all you have to do is to multiply the figures outside the bracket by the ones inside the brackets.

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I WILL MARK AS BRAINLIEST!!! What is the value of x?<br><br> 8x+3=43
uysha [10]
8x+3=43
-3 -3
8x=40
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X=5
8 0
3 years ago
Twelve less than 5 times a number is greater than or equal to 6 more than twice the number. Each inequality and number line repr
jenyasd209 [6]

Answer:  x ≥ 6

<u>Step-by-step explanation:</u>

12 less <u>than</u> 5 times a number ≥ 6 more <u>than</u> twice the number

                    5x - 12                    ≥                        2x + 6

Note: the word "than" switches the order of the terms.

5x - 12 ≥ 2x + 6

<u>-2x  +12</u>  <u>-2x +12 </u>

3x         ≥       18

<u>÷3         </u>     <u>    ÷3 </u>

   x         ≥       6

Graph: 6 -----------→   the dot is closed (filled in) since it is "equal to"

3 0
3 years ago
Pls solve the simultaneous equation in the attachment.
siniylev [52]

Answer:

Part a) The solution is the ordered pair (6,10)

Part b) The solutions are the ordered pairs (7,3) and (15,1.4)

Step-by-step explanation:

Part a) we have

\frac{x}{2}-\frac{y}{5}=1 ----> equation A

y-\frac{x}{3}=8 ----> equation B

Multiply equation A by 10 both sides to remove the fractions

5x-2y=10 ----> equation C

isolate the variable y in equation B

y=\frac{x}{3}+8 ----> equation D

we have the system of equations

5x-2y=10 ----> equation C

y=\frac{x}{3}+8 ----> equation D

Solve the system by substitution

substitute equation D in equation C

5x-2(\frac{x}{3}+8)=10

solve for x

5x-\frac{2x}{3}-16=10

Multiply by 3 both sides

15x-2x-48=30

15x-2x=48+30

Combine like terms

13x=78

x=6

<em>Find the value of y</em>

y=\frac{x}{3}+8

y=\frac{6}{3}+8

y=10

The solution is the ordered pair (6,10)

Part b) we have

xy=21 ---> equation A

x+5y=22 ----> equation B

isolate the variable x in the equation B

x=22-5y ----> equation C

substitute equation C in equation A

(22-5y)y=21

solve for y

22y-5y^2=21

5y^2-22y+21=0

Solve the quadratic equation by graphing

The solutions are y=1.4, y=3

see the attached figure

<em>Find the values of x</em>

For y=1.4

x=22-5(1.4)=15

For y=3

x=22-5(3)=7

therefore

The solutions are the ordered pairs (7,3) and (15,1.4)

3 0
4 years ago
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Answer:

N:ki n:kn:kNN

Step-by-step explanation:

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Use photo math or Socratic
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