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solmaris [256]
3 years ago
8

What is the midpoint of s segment in the complex plane with endpoints at 6-2i and -4+6i?

Mathematics
1 answer:
denis-greek [22]3 years ago
7 0
Get the average of the real and imaginary components: ½(6-4)+i/2(-2+6)=1+2i.
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. Given ????(5, −4) and T(−8,12):
damaskus [11]

Answer:

a)y=\dfrac{13x}{16}-\dfrac{129}{16}

b)y = \dfrac{13x}{16}+ \dfrac{37}{2}

Step-by-step explanation:

Given two points: S(5,-4) and T(-8,12)

Since in both questions,a and b, we're asked to find lines that are perpendicular to ST. So, we'll do that first!

Perpendicular to ST:

the equation of any line is given by: y = mx + c where, m is the slope(also known as gradient), and c is the y-intercept.

to find the perpendicular of ST <u>we first need to find the gradient of ST, using the gradient formula.</u>

m = \dfrac{y_2 - y_1}{x_2 - x_1}

the coordinates of S and T can be used here. (it doesn't matter if you choose them in any order: S can be either x_1 and y_1 or x_2 and y_2)

m = \dfrac{12 - (-4)}{(-8) - 5}

m = \dfrac{-16}{13}

to find the perpendicular of this gradient: we'll use:

m_1m_2=-1

both m_1and m_2 denote slopes that are perpendicular to each other. So if m_1 = \dfrac{12 - (-4)}{(-8) - 5}, then we can solve for m_2 for the slop of ther perpendicular!

\left(\dfrac{-16}{13}\right)m_2=-1

m_2=\dfrac{13}{16}:: this is the slope of the perpendicular

a) Line through S and Perpendicular to ST

to find any equation of the line all we need is the slope m and the points (x,y). And plug into the equation: (y - y_1) = m(x-x_1)

side note: you can also use the y = mx + c to find the equation of the line. both of these equations are the same. but I prefer (and also recommend) to use the former equation since the value of 'c' comes out on its own.

(y - y_1) = m(x-x_1)

we have the slope of the perpendicular to ST i.e m=\dfrac{13}{16}

and the line should pass throught S as well, i.e (5,-4). Plugging all these values in the equation we'll get.

(y - (-4)) = \dfrac{13}{16}(x-5)

y +4 = \dfrac{13x}{16}-\dfrac{65}{16}

y = \dfrac{13x}{16}-\dfrac{65}{16}-4

y=\dfrac{13x}{16}-\dfrac{129}{16}

this is the equation of the line that is perpendicular to ST and passes through S

a) Line through T and Perpendicular to ST

we'll do the same thing for T(-8,12)

(y - y_1) = m(x-x_1)

(y -12) = \dfrac{13}{16}(x+8)

y = \dfrac{13x}{16}+ \dfrac{104}{16}+12

y = \dfrac{13x}{16}+ \dfrac{37}{2}

this is the equation of the line that is perpendicular to ST and passes through T

7 0
3 years ago
15 POINTS WILL MARK BRAINLIEST!!!!! Choose the group responsible for the Declaration of Independence.
Bess [88]

Answer: second Congress

Step-by-step explanation:

Short and sweet

6 0
3 years ago
For all positive integers n, let *n* equal the greatest prime number that is a divisor of n. What does *10*/*12* equal?
artcher [175]

9514 1404 393

Answer:

  5/3

Step-by-step explanation:

The prime factorizations are ...

  10 = 2·5

  12 = 2·2·3

Then *10* = 5 and *12* = 3, so *10*/*12* = 5/3.

4 0
2 years ago
IOr — 5г + 3r — 8г i need help
Anni [7]

Answer:

0r

Step-by-step explanation:

Since they all have r you can pretend it s not there and add it on at the end.

Now 10 - 5 is 5. 5 + 3 is 8. 8 - 8 is 0. tack the r onto the end and you get 0r.

3 0
2 years ago
Please help<br><br><br><br> Thank yoy
BabaBlast [244]

Answer:

I think its graph 4

Step-by-step explanation:

7 0
2 years ago
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