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faust18 [17]
2 years ago
12

What is the volume of one rubber ball? round to the nearest hundredth of a centimeter. cm3 if the price of the rubber needed to

produce a ball is $0. 0045/cm3, what is the cost of producing one ball? round to the nearest cent. $ if the company sells a ball for $0. 50, how much profit will it make on each ball? $.
Mathematics
2 answers:
hoa [83]2 years ago
5 0

Answer:

20.58, 0.09, and 0.41.

Step-by-step explanation:

sertanlavr [38]2 years ago
3 0

The cost of producing one ball will be $ 0.09261. Then the profit will be if each ball is $ 0.41.

<h3>What is Geometry?</h3>

It deals with the size of geometry, region, and density of the different forms both 2D and 3D.

A toy company produces rubber balls that have a radius of 1. 7 cm.

A sphere has a radius of 1. 7 centimeters.

Then the volume of the ball will be

Volume = 4/3 x π x r³

Volume = 4/3 x π x 1.7³

Volume = 20.58 cubic cm

If the price of the rubber needed to produce a ball is $0.0045/cm³.

Then the cost of producing one ball will be

→ 20.58 x 0.0045

→ $ 0.09261

If the company sells a ball for $0.50. Then the profit will be

Profit = 0.50 - 0.09261

Profit = $ 0.41

More about the geometry link is given below.

brainly.com/question/7558603

#SPJ1

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Answer: The area of a sector is a fraction of the area of the circle. The fraction is equal to the ratio of the measure of the sector’s central angle to one full rotation, or 360°.

Step-by-step explanation:

3 0
3 years ago
(3 - i) + (1 - 2i) =
eimsori [14]
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$1,200, 3.9%, 8months
LUCKY_DIMON [66]
The answer is 1-28/2992/8 ow
3 0
3 years ago
You are planning a survey of starting salaries for recent computer science majors. In a recent survey by the National Associatio
nydimaria [60]

Answer:

A sample size of 554 is needed.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

Standard deviation is known to be $12,000

This means that \sigma = 12000

What sample size do you need to have a margin of error equal to $1000, with 95% confidence?

This is n for which M = 1000. So

M = z\frac{\sigma}{\sqrt{n}}

1000 = 1.96\frac{12000}{\sqrt{n}}

1000\sqrt{n} = 1.96*12

Dividing both sides by 1000:

\sqrt{n} = 1.96*12

(\sqrt{n})^2 = (1.96*12)^2

n = 553.2

Rounding up:

A sample size of 554 is needed.

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