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Darina [25.2K]
3 years ago
11

What is 14,11,8 sequence ​

Mathematics
1 answer:
TEA [102]3 years ago
8 0

Each step subtracts 3 from the previous number.

14 - 3 = 11

11 - 3 = 8

The sequence will continue:

8 - 3 = 5

5 - 3 = 2

2 - 3 = -1

Etc.

14, 11, 8, 5, 2, -1...

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A test was given to a group of students. The grades and gender are summarized below A B C TotalMale 5 9 2 16Female 7 11 12 30Tot
faust18 [17]

Probability that the student got a 'C' GIVEN they are female = number of females that got a C in the test/number of females

From the information given,

number of females that got a C in the test = 12

number of females = 30

Thus,

Probability that the student got a 'C' GIVEN they are female = 12/30

We would simplify the fraction by dividing the numerator and denominator by 6. Thus,

Probability that the student got a 'C' GIVEN they are female = 2/5

4 0
1 year ago
17. Evaluate each pair of expressions.<br> a. (-3)-8 and -3-8<br> b. (-3)-9 and -3-9
Semmy [17]
A = -11
B= -12

This is because of how calculations work in negatives. Because they are both negative they work similarly to addition
5 0
3 years ago
What is the formula for the area of a rectangle?
PtichkaEL [24]

Answer:

The area of a rectangle is length*width

Step-by-step explanation:

The answer is A

This is simple

6 0
3 years ago
Read 2 more answers
What are the roots of this equation? x2-4x+9=0
zysi [14]

Considering the definition of zeros of a function, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

<h3>Zeros of a function</h3>

The points where a polynomial function crosses the axis of the independent term (x) represent the so-called zeros of the function.

In summary, the roots or zeros of the quadratic function are those values ​​of x for which the expression is equal to 0. Graphically, the roots correspond to the abscissa of the points where the parabola intersects the x-axis.

In a quadratic function that has the form:

f(x)= ax² + bx + c

the zeros or roots are calculated by:

x1,x2=\frac{-b+-\sqrt{b^{2}-4ac } }{2a}

<h3>This case</h3>

The quadratic function is f(x) = x² + 4x +9

Being:

  • a= 1
  • b= 4
  • c= 9

the zeros or roots are calculated as:

x1=\frac{-4+\sqrt{4^{2}-4x1x9 } }{2x1}

x1=\frac{-4+\sqrt{16-36 } }{2x1}

x1=\frac{-4+\sqrt{-20 } }{2x1}

and

x2=\frac{-4-\sqrt{4^{2}-4x1x9 } }{2x1}

x2=\frac{-4-\sqrt{16-36 } }{2x1}

x2=\frac{-4-\sqrt{-20} }{2x1}

If the content of the root is negative, the root will have no solution within the set of real numbers. Then \sqrt{-20} has no solution.

Finally, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

Learn more about the zeros of a quadratic function:

brainly.com/question/842305

brainly.com/question/14477557

#SPJ1

6 0
1 year ago
How to use a 12th grade calculator
kondaur [170]
Click random buttons until you figure it out, or even ask a parent or teacher
4 0
1 year ago
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