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zysi [14]
3 years ago
9

......................................................

Mathematics
1 answer:
mafiozo [28]3 years ago
8 0
Hehe lovely what the
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Step-by-step explanation:

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5 0
3 years ago
A consumer group is testing camp stoves. To test the heating capacity of a stove, they measure the time required to bring 2 quar
kotykmax [81]

Answer:

a

The decision rule  is  

Reject the null hypothesis

  The conclusion is  

There is sufficient evidence to show that there is a difference between the performances of these two models

b

The  95% confidence interval is  0.224   <  \mu_1 - \mu_2  < 2.776

Step-by-step explanation:

From the question we are told that

    The sample size is  n  =  36

    The first sample mean is  \= x_1   =  11.4

    The first standard deviation is  s_1 =  2.5

    The second sample mean is   \= x_2 =  9.9

     The second standard deviation is  s_2 =  3.0

      The level of significance is  \alpha  =  0.05

The null hypothesis is  H_o  :  \mu_1 - \mu_2 = 0

The alternative hypothesis is H_a :  \mu_1 - \mu_2 \ne 0

Generally the test statistics is mathematically represented as

      z =  \frac{ (\= x_1 - \= x_2 ) - (\mu_1 - \mu_2 ) }{ \sqrt{ \frac{s_1^2 }{n} + \frac{s_2^2 }{ n}  } }

=>    z =  \frac{ ( 11.4  - 9.9) - 0  }{ \sqrt{ \frac{2.5^2 }{36} + \frac{ 3^2 }{36 }  } }

=>     z = 2.3

From the z table  the area under the normal curve to the left corresponding to  2.3 is  

       P( Z >  2.3 ) =  0.010724

Generally the p-value is mathematically represented as

      p-value =  2 * P( Z >  2.3 )

=>    p-value  =  2 * 0.010724

=>    p-value  =  0.02

From the value obtained we see that  p-value  <  \alpha hence  

The decision rule  is  

Reject the null hypothesis

  The conclusion is  

There is sufficient evidence to show that there is a difference between the performances of these two models

Considering question b

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

      E = Z_{\frac{\alpha }{2} } *  \sqrt{ \frac{s_1^2 }{n } + \frac{s_2^2}{n}}

 => E = 1.96  *    \sqrt{ \frac{2.5^2 }{ 36 } + \frac{ 3^2}{36}}

  => E = 1.276

Generally 95% confidence interval is mathematically represented as  

      ( \= x_1 - \= x_2) -E <  \mu_1 - \mu_2  < ( \= x_1 - \= x_2) + E

=>  ( 11.4 - 9.9 ) -1.276  <  \mu_1 - \mu_2 < ( 11.4 - 9.9 ) + 1.276

=>  0.224   <  \mu_1 - \mu_2  < 2.776

4 0
3 years ago
A building feet tall has a shadow that is feet long. Find the angle of elevation of the sun to the nearest hundredth of a degree
lina2011 [118]

Answer:

The angle of elevation of the sun to the nearest hundredth of a degree is 44.07°

Step-by-step explanation:

Here is the complete question:

A building 86.53 feet tall has a shadow that is 89.39 feet long. Find the angle of elevation of the sun to the nearest hundredth of a degree.

Step-by-step explanation:

Please see the attachment below for an illustrative diagram:

From the diagram

/AC/ is the height of the building

/CB/ is the length of the shadow

/AC/ = 86.53 feet

/CB/ 89.39 feet

θ is the angle of elevation

Consider triangle ABC

/AC/ is the opposite

and /CB/ is the adjacent

From

tanθ =\frac{Opposite}{Adjacent}

Then,

tanθ = \frac{/AC/}{/CB/}

tanθ = \frac{86.53}{89.39}

tanθ = 0.9680

∴θ = tan⁻¹(0.9680)

θ = 44.0686°

θ = 44.07° (to the nearest hundredth of a degree)

Hence, the angle of elevation of the sun to the nearest hundredth of a degree is 44.07°

8 0
3 years ago
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