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WITCHER [35]
2 years ago
5

What is the greatest common factor of 8 and 52

Mathematics
2 answers:
denis23 [38]2 years ago
6 0
The Greatest Common factor is 2
PilotLPTM [1.2K]2 years ago
4 0
The greatest common factor of 8 and 52 is 2.

<span><span>8:   222  </span><span>50:   2  55</span><span>GCF:   2  <span> 

</span></span></span>
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Write the following numbers in ascending order (from smallest to largest): 1.2, 3%, 3/5, 0.3, and -1 1/3. ​
SSSSS [86.1K]

Answer:

-1 1/3, 0.3, 1.2, 3/5,  3,  

Step-by-step explanation:

Hope I helped, can I plz have brainliest, ive never gotten one before!

5 0
2 years ago
2x<img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20-%2014x%20%2B%2024" id="TexFormula1" title="2x^{2} - 14x + 24" alt="2x^{2} -
choli [55]
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4 0
2 years ago
2+6i/2-4i = a + bi What is the value of a? What is the value of b?
Talja [164]

\dfrac{2+6i}{2-4i}\\\\\\=\dfrac{2(1+3i)}{2(1-2i)}\\\\\\=\dfrac{1+3i}{1-2i}\\\\\\=\dfrac{(1+3i)(1+2i)}{(1-2i)(1+2i)}\\\\\\=\dfrac{1+2i+3i+6i^2}{1-(2i)^2}\\\\\\=\dfrac{1+5i-6}{1+4}~~~~;[i^2=-1]\\\\\\=\dfrac{5i-5}{5}\\\\\\=\dfrac{5(i-1)}5\\\\=i-1\\\\=-1+i\\\\\text{It is in a form of a +bi so,}~ a = -1~ \text{and}~ b = 1

6 0
2 years ago
Consider the vectors a =3i +j −k, b =i +j +4k, c=i +3j +k, d =−i −3j +k, g =−3i −j +k. Which pairs (if any) of these vectors are
11111nata11111 [884]

Answer:

a and b are perpendicular to each other, as are b and d, b and g

Step-by-step explanation:

To check whether two vectors are perpendicular to each other, we need the angle between these vectors to be 90 degrees.

We can find the angle between to vectors a and b from the following relation:

The cosine of the angle \theta between two vectors is equal to the dot product of this vectors divided by the product of vector magnitude.

So

cos(\theta) = \frac{a.b}{|a||b|}

cos(90) = 0, so when the dot product between vectors a and b is 0, it means that these vectors are perpendicular to each other.

Now, for your exercise, let's compute the dot product between these vectors.

-----------

a.b = (3,1,-1).(1,1,4) = 3+1-4 = 0

So a and b are perpendicular to each other.

------------

a.c = (3,1,-1).(1,3,1) = 3+3-1 = 5

a and c are not perpendicular to each other.

--------------

a.d = (3,1,-1).(-1,-3,1) = -3-3-1 = -7

So not perpendicular

---------------

a.g = (3,1,-1).(-3,-1,1) = -9-1-1 = -11

Not

-----------------

b.c = (1,1,4).(1,3,1) = 1+3+4 = 8

Not

------------------

b.d = (1,1,4).(-1,-3,1) = -1 -3 +4 = 0

b.d = 0, so b and d are perpendicular to each other

--------------------

b.g = (1,1,4).(-3,-1,1) = -3-1+4 = 0

b.g = 0, perpendicular

---------------------

c.d = (1,3,1).(-1,-3,1) = -1-9+1 = -9

No

-----------------------

c.g = (1,3,1).(-3,-1,1) = -3-3+1 = -5

No

------------------------

d.g = (-1,-3,1).(-3,-1,1) = 3+3+1 = 7

No

7 0
3 years ago
If x = 5, y = 3 and z = 9 then evaluate the following expression: x-y+z=
Alex_Xolod [135]
<span> x-y+z=

x = 5
y = 3
z = 9

(5) - (3) + (9) = 
2 + 9 = 11

11 is the answer.

</span>
5 0
3 years ago
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