Answer:
12
Step-by-step explanation:12x9
Step-by-step explanation:
464.5cm³
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Answer:
The coordinates for B' would be (-6,1) and the coordinates for C would be (-8,-6)
Step-by-step explanation:
Point A was translated 2 left and 1 down to point A'
B = (-4,2)
-4 - 2 = -6 and 2 - 1 = 1 so B' would equal (-6,1)
C = (-6,-5)
-4 - 2 = -8 and -5 - 1 = -6 so C' would equal (-8,-6)
Answer:
(5,354 + x)
or
536.4*x
Step-by-step explanation:
We know that x = 10.
Now we want to write an expression (in terms of x) for the number 5,364.
This could be really trivial, remember that x = 10.
Then: (x - 10) = 0
And if we add zero to a number, the result is the same number, then if we add this to 5,364 the number does not change.
5,364 = 5,364 + (x - 10) = 5,364 + x - 10
5,364 = 5,354 + x
So (5,354 + x) is a expression for the number 5,364 in terms of x.
Of course, this is a really simple example, we could do a more complex case if we know that:
x/10 = 1
And the product between any real number and 1 is the same number.
Then:
(5,364)*(x/10) = 5,364
(5,364/10)*x = 5,364
536.4*x = 5,364
So we just found another expression for the number 5,364 in terms of x.
Answer:
P(X ≥ 1) = 0.50
Step-by-step explanation:
Given that:
The word "supercalifragilisticexpialidocious" has 34 letters in which 'i' appears 7 times in the word.
Then; the probability of success = 7/34 = 0.20588
Using Binomial distribution to determine the probability; we have:

where;
x = 0,1,2,...n and 0 < β < 1
and x represents the number of successes.
However; since the letter is drawn thrice; the probability that the letter "i" is drawn at least once can be computed as:
P(X ≥ 1) = 1 - P(X< 1)
P(X ≥ 1) = 1 - P(X =0)
![P(X \ge 1) = 1 - \bigg [ {^3C__0} (0.21)^0 (1-0.21)^{3-0} \bigg]](https://tex.z-dn.net/?f=P%28X%20%5Cge%201%29%20%3D%20%201%20-%20%5Cbigg%20%5B%20%7B%5E3C__0%7D%20%280.21%29%5E0%20%281-0.21%29%5E%7B3-0%7D%20%5Cbigg%5D)
![P(X \ge 1) = 1 - \bigg [ 1 \times 1 (0.79)^{3} \bigg]](https://tex.z-dn.net/?f=P%28X%20%5Cge%201%29%20%3D%20%201%20-%20%5Cbigg%20%5B%201%20%5Ctimes%201%20%280.79%29%5E%7B3%7D%20%5Cbigg%5D)
P(X ≥ 1) = 1 - 0.50
P(X ≥ 1) = 0.50