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damaskus [11]
4 years ago
13

Analysis showed that the mean arrival rate for vehicles at a certain Shell station on Friday afternoon last year was 4.5 vehicle

s per minute. How large a sample would be needed to estimate this year's mean arrival rate with 98 percent confidence and an error of ± 0.5?
Mathematics
2 answers:
Solnce55 [7]4 years ago
7 0

Answer:

25

Step-by-step explanation:

use a Poisson process to model the arrival.

the mean rate of arrivals  is λ=4.5

The standard deviation is calculated as:

σ==√λ =2.1213

The z-value for a 98% CI is z=2.3262.

If the 98% CI has to be within a error of 0.5 then:

Ul-Ll=2z*σ/√n=2*0.5=1

√n=z*σ=2.3262*2.1213=4.9346

√n=4.9346  and n = 4.9346^2=24.35 rounded to 25

The sample size needed is n=25.

nadezda [96]4 years ago
3 0

Answer:

idk sorry

Step-by-step explanation:

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a car travels at 54 km/h for first 20seconds , 36km/h for next 30seconds and finally 18km/h for next 10 seconds find the averade
Sladkaya [172]

Answer:

39 km/h

Step-by-step explanation:

Velocity is the rate of change of distance in a given direction with time. Mathematically,

Velocity = Displacement/time

Like speed, velocity is measured in Km/h or m/s.

Given that the car travels at 54 km/h for first 20seconds,

since 60 seconds = 1 minute and

60 minutes  = 1 h,

20 seconds

= 20/(60 ×60) h

= 1/180 h

In the same vein,

30 seconds

= 30 / (60 ×60) h

= 1/120 h

10 seconds

= 10/(60 ×60) h

= 1/360 h

Hence  if the car travels 54 km/h for 10 seconds, the distance covered

= 54 × 1/180

= 3/10 Km

If the car travels 36km/h for next 30seconds, the distance covered

= 36 × 1/120

= 3/10 Km

If the car travels 18km/h for next 10 seconds, the distance covered

= 18 × 1/360

= 1/20 km

Total distance = 3/10 Km + 3/10 Km + 1/20 Km

= 13/20 Km

Total time spent = 20 + 30 + 10

= 60 seconds

= 1/60 h

Average velocity = 13/20 km/ 1/60 h

= 39 Km/h

7 0
4 years ago
What is the area?<br> 20 in<br> 25 in<br> square inches
slava [35]

Answer:

<em>2</em><em>5</em><em>0</em><em> </em><em>in </em><em>sq</em>

Step-by-step explanation:

<em>Here's</em><em> the</em><em> solution</em>

<em>=</em><em>></em><em> </em><em>Base </em><em>=</em><em> </em><em>2</em><em>5</em><em>i</em><em>n</em><em> </em>

<em>=</em><em>></em><em> </em><em>Height</em><em> </em><em>=</em><em> </em><em>2</em><em>0</em><em>i</em><em>n</em>

<em>=</em><em>></em><em>We </em><em>need</em><em> to</em><em> </em><em>find </em><em>out</em><em> area</em><em> of</em><em> traingle</em>

<em>=</em><em>></em><em> </em><em>Area</em><em> of</em><em> </em><em>traingle </em><em>=</em><em> </em><em>1</em><em>/</em><em>2</em><em>*</em><em>base </em><em>*</em><em>height</em><em> </em>

<em>=</em><em>></em><em> </em><em>Area</em><em> </em><em>=</em><em> </em><em>1</em><em>/</em><em>2</em><em>*</em><em>2</em><em>0</em><em>*</em><em>2</em><em>5</em><em> </em>

<em>=</em><em>></em><em> </em><em>Area</em><em>=</em><em> </em><em>2</em><em>5</em><em>0</em><em> </em><em>in </em><em>sq</em>

<em>hope</em><em> it</em><em> helps</em><em>. </em><em> </em><em>^</em><em>_</em><em>^</em>

7 0
3 years ago
Read 2 more answers
You have $100 begging on February 1, 2009, you spend $1 each day. On what day do you spend your last dollar?
Leno4ka [110]

Is it a leap year? haha. But for real your anser will be May 11, 2009

7 0
3 years ago
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please solve the question and show your work so pluto is the farthest planet from the sun it also the slowest planet. plutos ave
allsm [11]
Knowing that pluto is travelling at 10,604 and the Earth travels 6.28 times faster; 

6.28x=10,604 mph (where x is the speed of the earth) 
x=10,604/6.28 
x=1688.53 mph for the Earth 

Double check by multiplying the answer found by 6.28 to see if it gives pluto's speed. 

1688.53×6.28=10, 604 mph 

Therefore, our solution is correct. 

Hope I helped :) 
3 0
3 years ago
HELP ME! thank youu!
Dvinal [7]

Answer:

y=51(Alternate interior angles)

z=40(Alternalte interior angles)

x=89(Sum of angles in a triangle)

5 0
3 years ago
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