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2 years ago

How to convert an equation to slope intercept form.

Mathematics

1 answer:

Marysya12 [62]2 years ago

5 0

Step-by-step explanation: (this is an example problem)

Write the form y=mx+b (The goal is to isolate the y).(m=3)(b=4)

y = 3x+4

↑ ↑

-3x -3x

∨

-3x+y=4

(sorry if this isn't a good explanation)

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Suppose that E(θˆ1) = E(θˆ2) = θ, V(θˆ 1) = σ2 1 , and V(θˆ2) = σ2 2 . Consider the estimator θˆ 3 = aθˆ 1 + (1 − a)θˆ 2. a Show

katen-ka-za [31]

Answer:

Step-by-step explanation:

Given that:

$E( \hat \theta _1) = \theta \ \ \ \ E( \hat \theta _2) = \theta \ \ \ \ V( \hat \theta _1) = \sigma_1^2 \ \ \ \ V(\hat \theta_2) = \sigma_2^2$

If we are to consider the estimator $\hat \theta _3 = a \hat \theta_1 + (1-a) \hat \theta_2$

a. Then, for $\hat \theta_3$ to be an unbiased estimator ; Then:

$E ( \hat \theta_3) = E ( a \hat \theta_1+ (1-a) \hat \theta_2)$

$E ( \hat \theta_3) = aE ( \theta_1) + (1-a) E ( \hat \theta_2)$

$E ( \hat \theta_3) = a \theta + (1-a) \theta = \theta$

b) If $\hat \theta _1 \ \ and \ \ \hat \theta_2$ are independent

$V(\hat \theta _3) = V (a \hat \theta_1+ (1-a) \hat \theta_2)$

$V(\hat \theta _3) = a ^2 V ( \hat \theta_1) + (1-a)^2 V ( \hat \theta_2)$

Thus; in order to minimize the variance of $\hat \theta_3$ ; then constant a can be determined as :

$V( \hat \theta_3) = a^2 \sigma_1^2 + (1-a)^2 \sigma^2_2$

Using differentiation:

$\dfrac{d}{da}(V \ \hat \theta_3) = 0 \implies 2a \ \sigma_1^2 + 2(1-a)(-1) \sigma_2^2 = 0$

⇒

$a (\sigma_1^2 + \sigma_2^2) = \sigma^2_2$

$\hat a = \dfrac{\sigma^2_2}{\sigma^2_1+\sigma^2_2}$

This implies that

$\dfrac{d}{da}(V \ \hat \theta_3)|_{a = \hat a} = 2 \ \sigma_1^2 + 2 \ \sigma_2^2 > 0$

So, $V( \hat \theta_3)$ is minimum when $\hat a = \dfrac{\sigma_2^2}{\sigma_1^2+\sigma_2^2}$

As such; $a = \dfrac{1}{2}$ if $\sigma_1^2 \ \ = \ \ \sigma_2^2$

4 0

4 years ago

Qual o resultado da subtração dos dois polinômios abaixo? (2x2 + 4x) (–2x2 + x – 6)

Len [333]

Answer:

-4x^4-6x^3-8x^2-24x

Step-by-step explanation:

$\left(2x^2+4x\right)\left(-2x^2+x-6\right)\\$

distribuir parênteses

$=2x^2\left(-2x^2\right)+2x^2x+2x^2\left(-6\right)+4x\left(-2x^2\right)+4xx+4x\left(-6\right)$

Aplicar regras de menos mais ; $+\left(-a\right)=-a$

$=-2\times\:2x^2x^2+2x^2x-2\times\:6x^2-4\times\:2x^2x+4xx-4\times\:6x$

simplificar

$-2\times\:2x^2x^2+2x^2x-2\times\:6x^2-4\times\:2x^2x+4xx-4\times\:6x:\\\quad -4x^4-6x^3-8x^2-24x$

7 0

4 years ago

How do you solve 8/14 = 2/x

mylen [45]

Answer:

x = 3 1/2

Step-by-step explanation:

8/14 = 2/x

Using cross products

8*x = 14*2

8x = 28

Divide by 8

8x/8 = 28/8

x = 7/2

x = 3 1/2

7 0

3 years ago

Is 3/5 and 21/35 equivalent

Stells [14]

Answer: Yes 3/5 and 21/35 are equivalent.

Step-by-step explanation:

3 ÷ 5 = 0.6

21 ÷ 35 = 0.6

3 0

3 years ago

Read 2 more answers

Two cars got an oil change at the same auto shop. The shop charges customers for each quart of oil plus a flat fee for labor. Th

zvonat [6]

The labor fee is $13.55 and each quart of oil is $2.25

Step-by-step explanation:

Let,

x be the amount of each quart of oil

y be the amount of labor fee

According to given statement;

5x+y=24.80 Eqn 1

7x+y=29.30 Eqn 2

Subtracting Eqn 1 from Eqn 2

$(7x+y)-(5x+y)=29.30-24.80\\7x+y-5x-y=4.50\\2x=4.50$

Dividing both sides by 2

$\frac{2x}{2}=\frac{4.50}{2}\\x=2.25$

Putting x=2.25 in Eqn 1

$5(2.25)+y=24.80\\11.25+y=24.80\\y=24.80-11.25\\y=13.55$

The labor fee is $13.55 and each quart of oil is $2.25

Keywords: linear equation, subtraction

Learn more about subtraction at:

#LearnwithBrainly

6 0

3 years ago