Answer:
a. 14 is a coefficient, and b is a variable.
This can be expanded to 14*b
b. 30 is a coefficient, and j and k are variables.
This can be expanded to 30*j*k
Answer:
(a) -7 , - 9 , - 11
(b) Arithmetic sequence
(c) There is a common difference of -2
(d) -53
Step-by-step explanation:
(a) To find the next three terms , we must firs check if it is arithmetic sequence or a geometric sequence . For it to be an arithmetic sequence , there must be a common difference :
check :
-3 - (-1) = -5 - (-3) = -7 - (-5) = -2
This means that there is a common difference of -2 , which means it is an arithmetic sequence.
The next 3 terms we are to find are: 5th term , 6th term and 7th term.
= a + 4d
= - 1 + 4 ( -2 )
= -1 - 8
= - 9
6th term = a +5d
= -1 + 5(-2)
= -1 - 10
= - 11
= a + 6d
= -1 + 6 (-2)
= -1 - 12
= -13
Therefore : the next 3 terms are : -9 , -11 , - 13
(b) it is an arithmetic sequence because there is a common difference which is -2
(c) Because of the existence of common difference
(d)
= a + 26d
= -1 + 26 ( -2 )
= -1 - 52
= - 53
Answer: f^-1(x)=-7x+3 maybe ? i think
Step-by-step explanation:
Answer: No Solution
Step-by-step explanation:
y=2x+1 and 2x-y=3
Substitute y=2x+1 into 2x-y=3
So you will have: 2x-2x+1=3
Then,
2x-2x=0
0+1=3
1=3
1 doesn't equal 3 so there is no solution.
Answer:
Both lights would flash together after every 30 seconds.
Step-by-step explanation:
6 = 2 * 3 and 10 = 2 * 5.
LCM (Least Common Multiple) of 6 and 10 = 2 * 3 * 5 = 30.
Therefore, both lights wold flash together after every 30 seconds.