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dolphi86 [110]
2 years ago
6

I need help 30 pionts if u help me!!!!

Mathematics
1 answer:
enyata [817]2 years ago
4 0
If you want to find the volume have to multiply the length times width times height


As so 2 x 9.6 x 10= 192
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The size of a typical virus is about 0.000008 centimeters, which can be
Reptile [31]
I wanna say it’s d because of the way it’s set up, i hope this helps if not i’m really really sorry
5 0
3 years ago
Read 2 more answers
Beth estimates her expenditures for transportation as follows: May, $91; June, $122; July $478. What is her estimated average mo
kipiarov [429]

Answer:

around 230

Step-by-step explanation:

91+122+478=691

691÷3= 230.33333333

4 0
3 years ago
The Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are
almond37 [142]

Answer:

For x = 0, P(x = 0) = 0.35

For x = 1, P(x = 1) = 0.54

For x = 2, P(x = 2) = 0.11

For x = 3, P(x = 3) = 0

Step-by-step explanation:

We are given that the Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are not. Three altimeters are randomly selected, one at a time, without replacement.

Let X = <u><em>the number that are not correctly calibrated.</em></u>

Number of altimeters that are correctly calibrated = 6

Number of altimeters that are not correctly calibrated = 2

Total number of altimeters = 6 + 2 = 8

(a) For x = 0: means there are 0 altimeters that are not correctly calibrated.

This means that all three selected altimeters are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = ^{8}C_3

The number of ways of selecting 3 altimeters from a total of 6 altimeters that are correctly calibrated = ^{6}C_3

So, the required probability = \frac{^{6}C_3}{^{8}C_3}  

                                              = \frac{20}{56}  = <u>0.35</u>

(b) For x = 1: means there is 1 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 1 is not correctly calibrated and 2 are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = ^{8}C_3

The number of ways of selecting 2 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = ^{6}C_2

The number of ways of selecting 1 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = ^{2}C_1

So, the required probability = \frac{^{6}C_2 \times ^{2}C_1 }{^{8}C_3}  

                                                = \frac{30}{56}  = <u>0.54</u>

(c) For x = 2: means there is 2 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 2 are not correctly calibrated and 1 is correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = ^{8}C_3

The number of ways of selecting 1 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = ^{6}C_1

The number of ways of selecting 2 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = ^{2}C_2

So, the required probability = \frac{^{6}C_1 \times ^{2}C_2 }{^{8}C_3}  

                                                = \frac{6}{56}  = <u>0.11</u>

(d) For x = 3: means there is 3 altimeter that is not correctly calibrated.

This case is not possible, so this probability is 0.

6 0
3 years ago
24 . What is the length of Side Of BC <br> A 3<br> C 10<br> B 8<br> D 24
jekas [21]

Answer:

B (8)

Step-by-step explanation:

AB = BC = AC

AB = BC

x+5 = 3x-1

6 = 2x

x = 3

BC = 3x-1 = 3*3 - 1 = 8

7 0
3 years ago
Read 2 more answers
the length of each side of a square is 3 in. more than the length of each side of a similar square. The sum of the areas of the
jeyben [28]

Answer:

20008.3333333

Step-by-step explanation:

3 0
3 years ago
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