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2 years ago

I need help 30 pionts if u help me!!!!

Mathematics

1 answer:

enyata [817]2 years ago

4 0

If you want to find the volume have to multiply the length times width times height

As so 2 x 9.6 x 10= 192

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56 / 8 please hurry

viktelen [127]

56 divided by 8 = 7
Hope it helps :)

7 0

3 years ago

Nadir saves $1 the first day of a month, $2 the second day, $4 the third day, and so on. He continues to double his savings each

zlopas [31]

Answer:

$16,384

Step-by-step explanation:

The amount of money Nadir saves increases exponentially by a factor of 2. If you keep multiplying each previous number by 2 until you get to the 15th number, (2*2, 4*2, 8*2, 16*2), you will get 16,384.

4 0

4 years ago

Read 2 more answers

Charlie has 5 times as many stamps as Ryan. They have 1,608 stamps in all. How many more stamps does CHarlie have than Ryan?

Leokris [45]

So,
The ratio of Ryan to Charlie is 1:5
Ryan=x
Charlie=5x
5x+x=1608
6x=1608
Divide both sides by 6
1608/6=268
x=268
Ryan has 268 stamps.
Charlie has 5(268) 1340 stamps.
1340+268=1608
1340-268=1072.
Charlie has 1072 more stickers than Ryan.

Hope I helped!

4 0

3 years ago

Need help with thissss!!

mario62 [17]

Answer:

f(5) = 38

Step-by-step explanation:

f(a) = 7(a + 1) - 4

f(5) = 7(5 + 1) - 4

f(5) = 7(6) - 4

f(5) = 42 - 4

f(5) = 38

4 0

3 years ago

Write a word problem about equal groups<br><br><br> and act it out to solve.

lina2011 [118]

Answer:

One scientist was working two molecules:

$BF_{3}, SO_{3}$

And verified that geometrically speaking, those are trigonal planar molecules made up of an equilateral triangle. He designed both molecules and classified them as Plane dihedral Groups. Was he correct? Why?

Step-by-step explanation:

Yes He was right. Place one atom in the centroid of the equilateral triangle (S or B), and each atom in each vertex(O or F).

We can apply geometric transformations (plane) rotations: R0, R2π/3, R4π/3

(And spatial ones, as R1, R2, R3 180º rotation over each median.)

Composite functions show that this is not an Abelian Group:

$R_{1}\circ\:R_{2}=R_{\frac{2\pi}{3}}\\R_{2}\circ\:R_{1}=R_{\frac{4\pi}{3}}\\$

7 0

3 years ago