I believe the answer would be 300. One eighth of the class would be 100 and 1/2 of the class would be 400. 800-(400+100)=300. Hope this helped!
<h3 /><h3>▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄</h3><h3>Required Solution :</h3>
Let the first even number be 'x' & the second even number be (x + 2)
<u>According to the Question</u>,
⇒x + (x + 2) = 34
⇒x + x + 2 = 34
⇒2x + 2 = 34
⇒2x = 34 - 2
⇒2x = 32
⇒x = 32/2
⇒x = 16
⇒First even number = x = 16
⇒Second even number = (x + 2) = 16 + 2 = 18
<u>∴</u><u> </u><u>The t</u><u>wo consecutive even n</u><u>u</u><u>m</u><u>b</u><u>e</u><u>r</u><u>s</u><u> are 16 & 18</u> ...!
<h3>Verefication : </h3>
As, In our Question it was given that "The sum of two consecutive even numbers is thirty-four". So, as we got our two consecutive even numbers as 16 & 18 ... By this, we can say that these both even numbers should be equals to 34, i.e., 16 + 18 = 34. Hence, The equation which we formed is correct ...!
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Answer:
2
Step-by-step explanation:
9x + 9 = 25 + x
8x = 16
x = 2
make sure to ask if you need any further guidance.
