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Mila [183]
4 years ago
10

At a company fish fry, 1/2 in attendance are employees. Employees’ spouses are 1/3 of the attendance. What is the percentage of

the people in attendance who are NOT employees or employee spouses?
SHOW WORK
Mathematics
1 answer:
Lelechka [254]4 years ago
8 0

Answer:At a company fish fry, 1/2 in attendance are employees.

Employees’ spouses are 1/3 of the attendance. What is

the percentage of the people in attendance who are not

employees or employee's spouses?


One half of X are employees.

One third of X are employee's spouses.



Step-by-step explanation:1/2 + 1/3 = 3/6 + 2/6 = 5/6


Then we subtract that fraction from one whole, or 1,

to see what fraction is left.  That is, we say


1 minus 5/6


which is


1 - 5/6


Now write 1 as 6/6


6/6 - 5/6


We get 1/6


So 1/6 is left.  Now we need to make that into

a percent by multiplying it by 100 and tacking on a "%"


1/6 × 100


1/6 × 100/1


100/6


50/3


16 2/3 %


So 16 2/3 % of the people in

attendance are neither employees

nor employee's spouses.



Now let's check:


1/2 are employees.  That's 50%

1/3 are wmployee's spouses. That's 33 1/3%

15 2/3 % are neither employees nor employee's spouses.


Add them up


50     %

33 1/3 %

16 2/3 %

--------

99 3/3 %


And 99 3/3% = 100%



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