Descompuneti in factori. x^2+4x-5=?

1 answer:

3 0

<span>Assume that,
x^2+4x-5 = 0 .......(1)
Then, x^2+4x-5 = 0 x^2+5x-1x-5 =0
x(x+5)-1(x+5) = 0
(x+5) (x-1) = 0
We get x=-5 and x=1
Sub x=-5 in equ (1)
(-5)^2+4(5)-5 = 0
-25+20-5 = 0
-25+25= 0
0 = 0
Sub x=1 in equ (1) (1)^2+4(1)-5 = 0
1+4-5 = 0 5-5 = 0
0 = 0
Therefore x value is -5 and 1</span>

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