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Damm [24]
4 years ago
8

Total amount if $500 is invested at 4% compounded annually for 10 years

Mathematics
1 answer:
ycow [4]4 years ago
3 0
P(10) = P(2.7183) ^ 0.04 times 10
P(10) = P(2.7183) ^ 0.4
P(10) = P(<span>1.49182868673)
P(10) = </span><span>745.914343367
Rounded, it would be 746. Hope it </span>helps! :)
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What is the common denominator for 1/2 and 1/8
Snowcat [4.5K]

Answer:


Step-by-step explanation:

8 would be the common denominator, so you would multiply the 1/2 by 4/4 to get 4/8, and if you needed to add, 4/8 + 1/8 is 5/8

7 0
4 years ago
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20.3 is 4 times as large as some number. What is the number?
neonofarm [45]
The answer would be 81.2 because all you gotta do it 20.3 times 4

7 0
3 years ago
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mrs.beluga is driving on a snow covered road with a drag factor of 0.2. she brakes suddenly for a deer. The tires leave a yaw ma
Aneli [31]
First, we are going to find the radius of the yaw mark. To do that we are going to use the formula: r= \frac{c^2}{8m} + \frac{m}{2}
where 
c is the length of the chord 
m is the middle ordinate 
We know from our problem that the tires leave a yaw mark with a 52 foot chord and a middle ornate of 6 feet, so c=52 and m=6. Lets replace those values in our formula:
r= \frac{52^2}{8(6)} + \frac{6}{2}
r= \frac{2704}{48} +3
r= \frac{169}{3} +3
r= \frac{178}{3}

Next, to find the minimum speed, we are going to use the formula: s= \sqrt{15fr}
where
f is <span>drag factor
</span>r is the radius 
We know form our problem that the drag factor is 0.2, so f=0.2. We also know from our previous calculation that the radius is \frac{178}{3}, so r= \frac{178}{3}. Lets replace those values in our formula:
s= \sqrt{(15)(0.2)( \frac{178}{3}) }
s= \sqrt{178}
s=13.34 mph

We can conclude that Mrs. Beluga's minimum speed before she applied the brakes was 13.34 miles per hour. 
8 0
4 years ago
Multiplying Integers 2.2 <br>-6.(-6) • (-6)​
Kamila [148]

Answer:

−475.2

hope this helps B) hope we can be friends UvU

Step-by-step explanation:

3 0
3 years ago
If f(x) = 2x^3 - 14x^2 + 38x -26 and x-1 is a factor of f(x) find all of the zeros of f(x) algebraically.
Anestetic [448]

Answer:

Step-by-step explanation:

First confirm that x = 1 is one of the zeros.

f(1) = 2(1)^3 - 14(1)^2 + 38(1) - 26

f(1) = 2 - 14 + 38 - 26

f(1) = -12 + 38 = + 26

f(1) = 26 - 26

f(1) = 0

=========================

next perform a long division

x -1  || 2x^3 - 14x^2 + 38x - 26 || 2x^2 - 12x + 26

          2x^3 - 2x^2

          ===========

                    -12x^2 + 28x

                     -12x^2 +12x

                     ==========

                                  26x -26

                                  26x - 26

                                 ========

                                      0

Now you can factor 2x^2 - 12x + 26

                                 2(x^2 - 6x + 13)

The discriminate of the quadratic is negative. (36 - 4*1*13) = - 16

So you are going to get a complex result.

x = -(-6) +/- sqrt(-16)

     =============

                 2

x  = 3 +/- 2i

f(x) = 2*(x - 1)*(x - 3 + 2i)*(x - 3 - 2i)

The zeros are

1

3 +/- 2i

8 0
4 years ago
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