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3 years ago

What is the point-slope form of a line with slope 3 that contains the point (2,1)

Mathematics

1 answer:

Ilya [14]3 years ago

4 0

<h3>Answer: y - 1 = 3(x - 2)</h3>

Explanation:

The point-slope form is this general template

y - y1 = m(x - x1)

We replace m with the given slope 3, so we get to this

y - y1 = 3(x - x1)

Then replace the given point (x1, y1) with (2, 1) to end up with

y - 1 = 3(x - 2)

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Consider the following expression and determine which statements are true. m+(5n)(9-p)-6-r^2

Fed [463]

Answer:

(B)The expression (5n)(9-p) is the product

(D)The expression 9-p has exactly two terms

Step-by-step explanation:

In the expression;

$m+(5n)(9-p)-6-r^2$

The coefficient of m is 1, therefore Option A is not true

The product of 5n and 9-p is (5n)(9-p), therefore Option B is true.

The expression 9-p has exactly two terms,9 and p.

Therefore, Options B and D are true.

6 0

3 years ago

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100 points!!! i will award brainliest!! Lines AB, and CD are straight lines. Find x and y

Ket [755]

<O = 16 degrees vertical angles are equal

<O + 4x+90 = 180 DC is a straight line

16 +4x +90 = 180

106 +4x = 180

4x =74

x =18.5

16 +90 +2y= 180 DC is a straight line

106+2y=180

2y = 74

y= 37

Answer : y=37

x=18.5

3 0

3 years ago

Read 2 more answers

Please help hurry. Drag each number to the correct location on the table.

Kaylis [27]

Answer:

Between -2 and 1 is -0.5 and 0.5

Below -2 is -4.5 and -2.5

Above 1 is 4 and 1.5

Step-by-step explanation:

Can i have brainliest?

8 0

3 years ago

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A study of 35 golfers showed that their average score on a particular course was 92. The sample standard deviation was 5. We wan

svlad2 [7]

Answer:

$t_{\alpha/2} = t_{0.05/2} = t_{0.025} = 2.0322$

Step-by-step explanation:

We have a sample of size n = 35, $\bar{x} = 92$ and $s = 5$ . As we want to construct a 95% confidence interval to estimate the value of the true population mean $\mu$ , we should use the pivotal quantity given by $T = \frac{\bar{X}-\mu}{S/\sqrt{n}}$ which comes from the t distribution with n - 1 = 35 - 1 = 34 degrees of freedom. Besides we should use the t-value $t_{\alpha/2} = t_{0.05/2} = t_{0.025} = 2.0322$ , i.e., regarding the t-distribution with 34 degrees of freedom, we have an area of 0.025 above 2.0322 and below the probability density function. The rationale behind this is that $P(-2.0322\leq T\leq 2.0322) = 0.95$ because of the simmetry of the t distribution.