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2 years ago

What is the point-slope form of a line with slope 3 that contains the point (2,1)

Mathematics

1 answer:

Ilya [14]2 years ago

4 0

<h3>Answer: y - 1 = 3(x - 2)</h3>

Explanation:

The point-slope form is this general template

y - y1 = m(x - x1)

We replace m with the given slope 3, so we get to this

y - y1 = 3(x - x1)

Then replace the given point (x1, y1) with (2, 1) to end up with

y - 1 = 3(x - 2)

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Circle A has been enlarged to create circle A'. The table below shows the circumference of both circles.

stich3 [128]

Answer:

Option (2) 1.5

Step-by-step explanation:

Rule for the dilation of an image by a scale factor is,

Scale factor = $\frac{\text{Radius of image circle A'}}{\text{Radius of pre-image A}}=\frac{r'}{r}$

= $\frac{(2\pi) r'}{(2\pi) r}$

= $\frac{\text{Circumference of image}}{\text{Circumference of pre-image}}$

= $\frac{10.5}{7}$

= 1.5

Therefore, scale factor was used to create a circle A' = 1.5

Option (2) will be the correct option.

8 0

3 years ago

Need help with mean , median , mode question<br> + a few more..

Andreas93 [3]

Answer:

Mean:

a) 4

b) 2

c) 2

d) 2

Median:

a) 4,2

b) 5,2

c) 5,1

d) 4,1

Mode:

a) 1

b) 1

c) 1

d) 1

Step-by-step explanation:

Mean:

a) 1+4+2+1 = 8/4=4

b)1+5+2+1 = 9/4= 2.25 (round to the nearest whole number = 2)

c) 1+5+1+0 = 7/4 = 1.75 (round to the nearest whole number = 2)

d) 1+4+1+0 = 6/4 = 1.5 (round to the nearest whole number = 2)

3 0

3 years ago

Figure ABCD is a parallelogram.

Eddi Din [679]

Answer:

stack AD with bar on top space text is parallel to end text BC with bar on top.

3 0

2 years ago

Read 2 more answers

Cain has 40 eggs. He divides all the eggs and places an equal number into 10 small containers. How many eggs are in each contain

Tema [17]

Answer:

Step-by-step explanation:

40 ÷ 10 = 4

7 0

3 years ago

Read 2 more answers

Jane must get at least three of the four problems on the exam correct to get an A. She has been able to do 80% of the problems o

NISA [10]

Answer:

a) There is n 81.92% probability that she gets an A.

b) If she gets the first problem correct, there is an 89.6% probability that she gets an A.

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the answer is correct, or it is not. This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

For this problem, we have that:

The probability she gets any problem correct is 0.8, so $\pi = 0.8$ .

(a) What is the probability she gets an A?

There are four problems, so $n = 4$

Jane must get at least three of the four problems on the exam correct to get an A.

So, we need to find $P(X \geq 3)$

$P(X \geq 3) = P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 3) = C_{4,3}.(0.80)^{3}.(0.2)^{1} = 0.4096$

$P(X = 4) = C_{4,4}.(0.80)^{4}.(0.2)^{0} = 0.4096$

$P(X \geq 3) = P(X = 3) + P(X = 4) = 2*0.4096 = 0.8192$

There is n 81.92% probability that she gets an A.

(b) If she gets the first problem correct, what is the probability she gets an A?

Now, there are only 3 problems left, so $n = 3$

To get an A, she must get at least 2 of them right, since one(the first one) she has already got it correct.

So, we need to find $P(X \geq 2)$

$P(X \geq 3) = P(X = 2) + P(X = 3)$

$P(X = 2) = C_{3,2}.(0.80)^{2}.(0.2)^{1} = 0.384$

$P(X = 4) = C_{3,3}.(0.80)^{3}.(0.2)^{0} = 0.512$

$P(X \geq 3) = P(X = 2) + P(X = 3) = 0.384 + 0.512 = 0.896$

If she gets the first problem correct, there is an 89.6% probability that she gets an A.

3 0

3 years ago

What is the point-slope form of a line with slope 3 that contains the point (2,1)​

What is the point-slope form of a line with slope 3 that contains the point (2,1)