<span>The International Space Station orbits Earth at an altitude of 240 miles. If a camera were set up on the Space Station, Earth's horizon will be seen by the camera in a distance of </span><span>A. 480.31 miles.</span>

5 0

3 years ago

The width of a rectangle is 6n - 2.5 feet and the length is 2.5 + 8 feet. Find the perimeter of the rectangle.

ludmilkaskok [199]

I was thinking the measurement for ;length should be 2.5n + 8 feet since width is 6n -2.5 feet , but you gave 2.5+ 8 feet, so i will solve it in both ways

Answer: Perimeter = 5 + 12n + 11 feet ; Perimeter = 17n+ 11 feet

Step-by-step explanation:

Using Length = 2.5+ 8 feet,

Perimeter of a rectangle is calculated as 2( l+ b)

Given that width=6n - 2.5 feet

length =2.5 + 8 feet

Perimeter =2( l+ b)= 2L + 2B

Perimeter= 2(2.5 + 8feet ) + 2( 6n - 2.5 feet)

Perimeter = 5 + 16feet + 12n - 5feet

Perimeter = 5 + 12n + 11 feet

Using Length = 2.5n+ 8 feet,

Perimeter of a rectangle is calculated as 2( l+ b)

Given that width=6n - 2.5 feet

length =2.5n+ 8 feet

Perimeter =2( l+ b)= 2L + 2B

Perimeter= 2(2.5n + 8feet ) + 2( 6n - 2.5 feet)

Perimeter = 5n + 16feet + 12n - 5feet

Perimeter = 5n + 12n + 11 feet

Perimeter = 17n+ 11 feet

6 0

3 years ago

A 90% confidence interval for the mean height of students

Westkost [7]

Answer:

$ME= \frac{69.397-60.128}{2}= 4.6345 \approx 4.635$

And the best answer on this case would be:

b) m = 4.635

Step-by-step explanation:

Let X the random variable of interest and we know that the confidence interval for the population mean $\mu$ is given by this formula:

$\bar X \pm t_{\alpha/2} \frac{s}{\sqrt{n}}$

The confidence level on this case is 0.9 and the significance $\alpha=1-0.9=0.1$

The confidence interval calculated on this case is $60.128 \leq \mu \leq 69.397$

The margin of error for this confidence interval is given by:

$ME =t_{\alpha/2} \frac{s}{\sqrt{n}}$

Since the confidence interval is symmetrical we can estimate the margin of error with the following formula:

$ME = \frac{Upper -Lower}{2}$

Where Upper and Lower represent the bounds for the confidence interval calculated and replacing we got:

$ME= \frac{69.397-60.128}{2}= 4.6345 \approx 4.635$

And the best answer on this case would be:

b) m = 4.635

4 0

3 years ago