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Mila [183]
3 years ago
14

∆ABC =~ ∆DEF

Mathematics
2 answers:
Citrus2011 [14]3 years ago
5 0

Answer:

∠E

Step-by-step explanation:

In ABC, we see that vertex B correspond to the end of the short leg of the triangle.

we simply go to DEF and try to find the same corresponding vertex that is at the end of the short leg of triangle DEF.

in this case, we can clearly observe that it is vertex E# and hence angle E is the answer.

earnstyle [38]3 years ago
3 0

Answer:

angle E

Step-by-step explanation:

YOYOU CAN CUT BOTH OF THEM AND PLACE IT IN TOP OF EACH OTHER

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Find the area of isosceles triangle whose each side is 13cm and base 24cm.show by heron's formula!!
Annette [7]

Answer:

60

Step-by-step explanation:

13*24=60

formula is b*h/2 so

im trash :3

7 0
3 years ago
Read 2 more answers
Which shows one way to determine the factors of x3 – 9x2 + 5x – 45 by grouping?
Valentin [98]
Factoring by grouping usually pairs up the first 2 sets of expressions with the second 2 sets.  Ours looks like this, then:  (x^3-9x^2)+(5x-45)=0.  If we factor out the common x-squared in the first set of parenthesis, along with factoring out the common 5 in the second set, we get this:  x^2(x-9)+5(x-9).  Now the common expression that can be factored out is the (x-9).  When we do that, here's what it looks like:  (x-9)(x^2+5).  I'm not sure how far you are going with this.  You could set each of those equal to 0 and solve for x in each case.  The first one is easy.  If x - 9 = 0, then x = 9.  The second one involves the imaginary i since x^2 = -5.  In that case,  x=i \sqrt{5},-i \sqrt{5}.  Hopefully, in what I have given you, you can find what you're looking for.
7 0
3 years ago
Hunter and Brian are creating a poster for a project and they need to combine two different size boards to create their project.
shepuryov [24]

Answer:

<em>The maximum area of the second board must be (5x^2+3x-6) square inches.</em>

Step-by-step explanation:

The total area of two different size boards cannot exceed (7x^2-6x+2) square inches.

The area of one board is  (2x^2-9x+8) square inches.

Suppose, the area of the second board is  y square inches.

That means......

y+(2x^2-9x+8)\leq 7x^2-6x+2\\ \\ y\leq (7x^2-6x+2)-(2x^2-9x+8)\\ \\y \leq 7x^2-6x+2-2x^2+9x-8\\ \\ y\leq 5x^2+3x-6

So, the maximum area of the second board must be (5x^2+3x-6) square inches.

7 0
3 years ago
Read 2 more answers
On an interval of [0, 2π), can the sine and cosine values of a radian measure ever be equal? If so, enter the radian measure(s)
Lisa [10]

Answer:

Yes, they are equal in the values (in radians):

π/4, 5π/4

If cos(x) and sin(x) are defined to you as nonnegative functions (in terms of lengths), then 3π/4 and 7π/4 are also included

Step-by-step explanation:

Remember that odd multiples of 45° are special angles, with the same sine and cosine values (you can prove this, for example, by considering a right triangle with an angle of 45° and hypotenuse with length 1, and finding the trigonometric ratios).

The radian measure of 45° corresponds to π/4, hence the odd multiples on the interval [0, 2π) are π/4, 3π/4, 5π/4, 7π/4.

If you define sin(x) and cos(x) using the cartesian coordinate system (via unit circle), then cos(3π/4)=-sin(3π/4) and cos(7π/4)=-sin(7π/4). In this case, only π/4 and 5π/4 are valid choices.  

6 0
3 years ago
Which inequality is equivalent to |x-4|&lt;9
Lorico [155]

Answer with explanation:

The Given Inequality is

  |x-4|<9

Modulus of a number yields always a positive value.

→|x-4|= x-4, when, x-4≥0

                     That is , x≥4.

         = -(x-4), when, x-4<0

                    means, x<4.

     it can be Written as

 → -9<x-4<9

→ -9+4 < x -4+4 < 9+4

→ -5<x<13

→x∈(-5,13)

8 0
3 years ago
Read 2 more answers
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