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Komok [63]
2 years ago
11

Can someone help me with this? I don't understand how to solve it. (3x^2a - 4y^az^3a)^2

Mathematics
1 answer:
EastWind [94]2 years ago
6 0

(3x²ᵃ - 4yᵃz³ᵃ)² =

= 9x⁴ᵃ - 12x²ᵃyᵃz³ᵃ + 16y²ᵃz6ᵃ

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7,857,462 into scientific notation
motikmotik

Answer:

7.857462 × 10^6

Step-by-step explanation:

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3 years ago
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The composite figure is made up of a rectangle and two pentagons. find the area.
Elis [28]

The area of the pentagon is 5(1/2*9*13) = 5(58.5) = 292.5 square units.

There are 2 pentagons, so the area of the two are: 292.5 x 2 = 585 square units.

The area of the rectangle is 20 * 13 = 260 square units.


Total area = 260 + 585 = 845 square units.


The answer is D.

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3 years ago
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The mean absolute deviation for 1,2,2,2,3,3,3,3,3,3,3,3,4,4,4,4,4,4,5
antoniya [11.8K]

Answer:

7/10

Step-by-step explanation:

To find the MAD or mean of absolute deviation, we first have to find the mean.

Part I. Finding the mean.

To find the mean we add all the numbers up and divide it by the total number of numbers.

So we get:

(1+2+2+2+3+3+3+3+3+3+3+3+4+4+4+4+4+4+4+5) as our sum. This adds up to a total of 60. Since we have a total of 20 numbers, we divide 60 by 20 and get 3. So now we need to find the MAD.

Part II. Finding the MAD.

To find the MAD, we take the absolute value of the mean minus the numbers and divide that by the number of numbers. So we get the MAD to be 14/20 or 7/10.

3 0
2 years ago
What is the greatest common factor of the terms in the polynomial 12x4 + 27x3 + 6x2?
VikaD [51]

Step-by-step explanation:

We're going to be factoring:

12 {x}^{4}  + 27 {x}^{3}  + 6 {x}^{2}

We know that the GCF between 12, 27, and 6 is 3.

We also know that the GCF of x^4, x^3, and x^2 is x^2.

<u>When factoring:</u>

  • Use both of our GCFs, 3 and x^2 (3x^2).
  • Divide our coefficients by the GCF.

3{x}^{2} (4 {x}^{2}  + 9x + 2)

We know 3x^2 is the correct option since the polynomial is factored completely.

4 0
2 years ago
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Help my homework pls!!!!!!​
Hitman42 [59]

Answer:

(2x^2 + x-3)/(4x^2-9)

Step-by-step explanation:

The denominator looks like an expression in which we have applied the difference of two squares to

In that case, we know that;

a^2-b^2 = (a-b)(a+ b)

That means we would be have 2x + 3 as the other denominator factor and the expression at the denominator would be;

(2x + 3)(2x-3) = 4x^2 - 9

Also, we would have to cancel out 2x + 3 from the numerator too, so as to be left with only the binomial

That means;

(2x+3)(x-1) = 2x^2-2x+ 3x - 3 = 2x^2+x -3

So we have the original expression as;

(2x^2 + x-3)/(4x^2-9)

4 0
3 years ago
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