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quester [9]
3 years ago
8

Which describes all possible values of f(x) in the function f(x) = √x/2? All real numbers all real numbers except for 0 all posi

tive real numbers and 0 all negative real numbers and 0
Mathematics
1 answer:
Pachacha [2.7K]3 years ago
6 0

Answer:

all positive real numbers and 0

Step-by-step explanation:

The function has a square root in the x value, so this function can't have negative values, because a negative value of x would give a complex number for f(x), and positive values of x gives positive values of f(x).

The function f(x) can be zero, if the value of x is zero:

f(0) = \sqrt{0} /2 = 0/2 = 0

So the function f(x) can only have positive values and the value 0.

Correct option: "all positive real numbers and 0"

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Finn collected 4 3/8 pounds of newspaper for the recycling drive, Neil collected 2 times as
s344n2d4d5 [400]

Answer:

Finn collected 45 1/9 pounds of newspaper [mixed fraction]

Finn collected 406/9 pounds of newspaper [proper fraction]

Step-by-step explanation:

We know Neil collected 4 5/6 pounds of newspaper and Finn collected 9 1/3 times that amount. The question asks us to perform a fraction product, where each one is a mixed fraction.

Finn collected

4 5/6 x 9 1/3

Each fraction will be converted to proper fraction

Jonah collected 45 1/9 pounds of newspaper [mixed fraction]

Jonah collected 406 1/9 pounds of newspaper [proper fraction]

7 0
3 years ago
Given y = 4x + 3, what effect does changing the equation to y = 2x + 3 have on the slope? 
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The answer is C
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7 0
3 years ago
What is the solution to the equation below? Round to two decimal places. 2*in x=6.8
jek_recluse [69]

2\ln x=6.8\\ \ln x=3.4\\ x=e^{3.4}\approx29.96

7 0
4 years ago
|-5| – |-2| how do you do this. so you know this is high school work
makvit [3.9K]
=3
The absolute value of any number is ALWAYS positive. Negatives get changed to positives.
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8 0
3 years ago
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Autum school holding a voleturing challeng. Students are encouraged to volunteer for at least 1 1/2 hours per week. Volenteers a
Pani-rosa [81]

Given :

Challenge given is to volunteer for about 1 1/2 hours per week .

Autum did at a rate of 6 3/4 hours per week .

To Find :

The comparison ( ratio )  her volunteers rate with the challenge rate .

Solution :

Simplifying challenge rate in in normal fraction , 1\dfrac{1}{2}=\dfrac{2+1}{2}=\dfrac{3}{2} .

Also , simplifying her rate , 6\dfrac{3}{4}=\dfrac{(6\times 4)+3}{4}=\dfrac{27}{4} .

Now , ratio of his work by challenge is :

R=\dfrac{\dfrac{27}{4}}{\dfrac{3}{2}}\\\\\\R=\dfrac{27\times 2}{4\times 3}\\\\R=\dfrac{9}{2}

Therefore , the ratio is 9/2 or 4 1/2 .

Hence , this is the required solution .

8 0
4 years ago
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