Number of broken glasses / total glasses = 3/500 = 0.006 = 0.6%
The total weight of the two pieces together is 6 pounds.
<h3>How much would the two pieces weigh together?</h3>
A piece of raw silk that is 100 yards long by 1.25 yards wide weights 38lb.
Then, a piece that is 12.5 yards long (and still 1.25 yards wide) will weight:
M = (12.5/100)*38lb = 4.75 lb
And a piece of habotai silk that is 100 yards long by 1.25 yards wide weights 12lb.
Then, a piece that is 12.5 yards long will weigh:
M' = (12.5/100)*12lb = 1.5 lb
If we add these two, we get a total weight of:
M + M' = 4.5lb + 1.5lb = 6lb
The total weight of the two pieces together is 6 pounds.
If you want to learn more about weight:
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<span>1. Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats.
What is the theoretical probability that the family has two dogs or two cats?
25% chance
</span><span>2. Describe how to use two coins to simulate which two pets the family has.
</span>
You could use the coins to simulate which pet the family has by flipping them and having head be dog and tails be cat (or vice-versa).
<span>3. Flip both coins 50 times and record your data in a table like the one below.
</span><span>Based on your data, what is the experimental probability that the family has two dogs or two cats?
</span>
Based on the results, I concluded that for Heads, Heads (which could be dogs or cats) there was a 24% chance and for Tails, Tails there was a 26% chance
<span>4. If the family has three pets, what is the theoretical probability that they have three dogs or three cats?
1/8 chance (accidentally messed up there) or 12.5%
</span><span>5. How could you change the simulation to generate data for three pets?
</span><span>
To flip 3 coins and add more spots on the chart.
I hope that this helps because it took a while to write out. If it does, please rate as Brainliest
</span>
Answer:
9/27 or 9 to 27
Step-by-step explanation:
