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ludmilkaskok [199]
3 years ago
9

The sales tax for an item was $9.40 and it cost $470 before tax. find the sales tax rate. write your answer as a percentage.

Mathematics
1 answer:
ankoles [38]3 years ago
5 0
The sale tax would be the 2% of 470
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victus00 [196]

Answer:

Option B.

a

Step-by-step explanation:

Given:

-3( -x + a ) + 7 < 5     When x = -1

To Find:

a ?

Solution:

-3( -x + a ) + 7 < 5     When x = -1

Substitute x = -1 in above  we get

-3(-(-1) + a ) + 7 < 5

-3(1 + a) < 5 - 7

Using Distributive Property we get i.e A(B+C) = AB + AC

\therefore -3\times 1 +(-3)\times a

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Solve the simultaneous equations y=3x+2 and y=x+6
kogti [31]

Answer:

x=2

Step-by-step explanation:

y=3x+2

y=x+6

Since you're stating that, they both equal because equation is equated to equation 2 because of the Y.

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3x+2=x+6

3x-x=6-2  (bring 2 to the other side by subtracting 2 as well as x)

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2 years ago
A local fast-food restaurant can serve
Marizza181 [45]

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3 years ago
8 divided by two -thirds of x. PLS SOLVE THIS FOR ME ASAP​
Kaylis [27]

Answer:

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Step-by-step explanation:

8 divided by two-thirds of x is

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7 0
2 years ago
Use the following matrices, A, B, C and D to perform each operation.
wolverine [178]

Step-by-step explanation:

\bold{40.}\\\\A+B=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right] +\left[\begin{array}{ccc}4&1\\6&0\end{array}\right] =\left[\begin{array}{ccc}3+4&1+1\\5+6&7+0\end{array}\right]=\left[\begin{array}{ccc}7&1\\11&7\end{array}\right]

\bold{41.}\\\\B-A=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]-\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]=\left[\begin{array}{ccc}4-3&1-1\\6-5&0-7\end{array}\right]=\left[\begin{array}{ccc}1&0\\1&-7\end{array}\right]

\bold{42.}\\\\3C=3\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]=\left[\begin{array}{ccc}(3)(-2)&(3)(3)&(3)(1)\\(3)(-1)&(3)(0)&(3)(4)\end{array}\right]=\left[\begin{array}{ccc}-6&9&3\\-3&0&12\end{array}\right]

\bold{43.}\\\\CD=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]\\\\=\left[\begin{array}{ccc}(-2)(-2)+(3)(0)+(1)(3)&(-2)(3)+(3)(-2)+(1)(4)&(-2)(4)+(3)(1)+(1)(-1)\\(-1)(-2)+(0)(0)+(4)(3)&(-1)(3)+(0)(-2)+(4)(4)&(-1)(4)+(0)(1)+(4)(-1)\end{array}\right]\\\\=\left[\begin{array}{ccc}4+0+1&-6-6+4&-8+3-1\\2+0+12&-3+0+16&-4+0-4\end{array}\right]\\\\=\left[\begin{array}{ccc}5&-8&-6\\14&13&-8\end{array}\right]

\bold{44.}\\\\2D+3C=2\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]+3\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]\\\\=\left[\begin{array}{ccc}(2)(-2)&(2)(3)&(2)(4)\\(2)(0)&(2)(-2)&(2)(1)\\(2)(3)&(2)(4)&(2)(-1)\end{array}\right]+\left[\begin{array}{ccc}(3)(-2)&(3)(3)&(3)(1)\\(3)(-1)&(3)(0)&(3)(4)\end{array}\right]\\\\=\left[\begin{array}{ccc}-4&6&8\\0&-4&2\\6&8&-2\end{array}\right]+\left[\begin{array}{ccc}-6&9&3\\-3&0&12\end{array}\right]

\large\bold{You\ can\ not\ add\ matrices\ of\ different\ dimensions!!!}

4 0
2 years ago
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