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2 years ago

12

Solve each linear system by Elimination. 2x + 3y =2, 4x-2y=4

1 answer:

KonstantinChe [14]2 years ago

7 0

Answer:

Step-by-step explanation:

First, we will eliminate the x, so we multiply the first one by 2.

4x+6y=4

4x-2y=4

So, we have y=0, and we put that in the equations, so x is 1

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Janie and Jasmine are playing three games at an arcade. Each of the games requires either 2, 3, or 4 tokens. The girls plan to p

Brrunno [24]

Answer:

m+2n+2p=16 tokens or m+2(n+p)= 16 tokens

Step-by-step explanation:

First, we must understand how many tokens they have.

Janie played the 3-token game four times, so she used 12 tokens (3n x 4 = 12). Jasmine played the 4-token game five times, so she used 20 tokens (4p x 5 = 20).

Added up, the girls have 32 tokens (12+20 = 32 tokens (t)).

In order to play a round of the three games, 9 tokens are required (m+n+p = 9 / 2+3+4 = 9) by each girl. (32t-18t=14) 14 tokens are left after taking a ride in every game each. 14 left divided by 2 will leave 7 more tokens for each girl. You can split these 7 tokens into an n+p = 7 tokens

Thus,

Each girl can ride as follows:

m+2n+2p=16 tokens or m+2(n+p)= 16 tokens

4 0

3 years ago

Can someone help with 39-40 ???

Allisa [31]

39. 8 -0.7 are multiplied together so the answer is

(-0.7)^8

= 0.05765 to nearest 100 thousandth. ( using a calculator).

40. 10^4 + 0^12 = 10,000 + 0

= 10,000

6 0

3 years ago

The pastor divided the 3,000 circulars among 15 teenagers. How many circulars did each young person receive?

pav-90 [236]

Each young person received 200 circulars.

3,000/15= 200

7 0

3 years ago

Pam has 90 m of fencing to enclose an area in a petting zoo with two dividers to separate three types of young animals. The thre

andrew-mc [135]

Answer:

The area function is

$A=\frac{135}{2}x-\frac{9}{2}x^2$ .

The domain and range of A is $(0,15m)$ and $(0, 253.125 m^2]$ .

Step-by-step explanation:

The given length of fencing is $90 m$ .

Let the length and width of each pen be $x$ and $y$ respectively as shown in the figure.

As there are 3 pens, so, the total area,

$A= 3 xy \;\cdots (i)$

From the figure the total length of fencing is $6x+4y$ .

Here, for a significant area for the animals, $x>0$ as well as $y>0$ as $x$ and $y$ are the sides of ben.

From the given value:

$6x+4y=90\;\cdots (ii)$

$\Rightarrow y=\frac {45}{2}-\frac{3x}{2}$

Now, from equation (i)

$A=3x\left(\frac {45}{2}-\frac{3x}{2}\right)$

$\Rightarrow A=\frac{135}{2}x-\frac{9}{2}x^2\;\cdots (iii)$

This is the required area function in the terms of variable $x$ .

For the domain of area function, from equation (ii)

$x=15-\frac{2y}{3}$

$\Rightarrow x$ [as y>0]

So, the domain of area function is $(0,15m)$ .

For the range of area function:

As $x \rightarrow 0$ or $y\rightarrow 0$ , then $A\rightarrow 0$ [from equation (i)]

$\Rightarrow A>0$

Now, differentiate the area function with respect to $x$ .

$\frac {dA}{dx}=\frac{135}{2}-9x$

Equate $\frac {dA}{dx}$ to zero to get the extremum point.

$\frac {dA}{dx}=0$

$\Rightarrow \frac{135}{2}-9x=0$

$\Rightarrow x=\frac{15}{2}$

Check this point by double differentiation

$\frac {d^2A}{dx^2}=-9$

As, $\frac {d^2A}{dx^2}$ , so, point $x=\frac{15}{2}$ is corresponding to maxima.

Put this value back to equation (iii) to get the maximum value of area function. We have

$A=\frac{135}{2}\times \frac {15}{2}-\frac{9}{2}\times \left(\frac {15}{2}\right)^2$

$\Rightarrow A=253.125 m^2$

Hence, the range of area function is $(0, 253.125 m^2]$ .

4 0

3 years ago

How do i do this <br> f(x) = -3(3) + 2

ANTONII [103]

The answer is given above

3 0

3 years ago