Answer:
Step-by-step explanation:
We will make a table and fill it in according to the information provided. What this question is asking us to find, in the end, is how long did it take the cars to travel the same distance. In other words, how long, t, til car 1's distance = car 2's distance. The table looks like this:
d = r * t
car1
car2
We can fill in the rates right away:
d = r * t
car1 40
car2 60
Now it tells us that car 2 leaves 3 hours after car 1, so logically that means that car 1 has been driving 3 hours longer than car 2:
d = r * t
car1 40 t + 3
car2 60 t
Because distance = rate * time, the distances fill in like this:
d = r * t
car1 40(t + 3) = 40 t+3
car2 60t = 60 t
Going back to the interpretation of the original question, I am looking to solve for t when the distance of car 1 = the distance of car 2. Therefore,
40(t+3) = 60t and
40t + 120 = 60t and
120 = 20t so
t = 6 hours.
Answer:
3 minutes
Step-by-step explanation:
If Ms. Selwa can run 1/6 of a kilometer in a minute, she can run 3/6 of a kilometer in 3 minutes.
This is because 1/6 times 3 equals 3/6, which is the distance of the school from her home.
So, it will take Ms. Selwa 3 minutes to run to school.
Answer: She can randomly survey 50 seventh-graders in the school.
Step-by-step explanation: To get the best result without wasting to much time means she cannot afford to survey every student. To receive the best results it should be unbiased so random is the way to go. Randomly surveying 50 girls in her school does not guarantee that those girls are all seventh graders so the best answer is She can randomly survey 50 seventh-graders in the school.
The first one is Reflection. The second one is Translation but I’m not sure the the second one
<span>Construct the perpendicular to BC¯¯¯¯¯ through point R.</span>
