I'll do the first two problems to get you started. All problems shown will use the same formula.
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Problem 4
The formula to use is
C = 100*(B-A)/A
where
A = old value
B = new value
C = percent change
In this case, A = 12 and B = 36, so
C = 100*(B-A)/A
C = 100*(36-12)/12
C = 100*(24/12)
C = 100*2
C = 200%
We have a 200% increase. It is an increase because the value of C is positive.
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Problem 5
Use the same formula as in the previous problem. This time,
A = 75 is the old value
B = 25 is the new value
C = 100*(B-A)/A
C = 100*(25-75)/75
C = 100*(-50/75)
C = 100*(-2/3)
C = -66.6667%
C = -66.7%
The value of C is negative, so we have a percent decrease of roughly 66.7%
Using an exponential function, it is found that 4 mg of the substance would still be left after 32 days.
<h3>What is an exponential function?</h3>
A decaying exponential function is modeled by:

In which:
- A(0) is the initial value.
- r is the decay rate, as a decimal.
In this problem, considering that the initial amount if of 64 mg, and we are working with half-lifes, the equation is given by:

32 days is 32/8 = 4 half-lifes, hence the amount remaining in mg is given by:

More can be learned about exponential functions at brainly.com/question/25537936
Answer: r = 11
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Answer:
see below
Step-by-step explanation:
we are given a exponential function

we want to figure out the missing values of y for x i.e (-2,-1, and 2) to do we can consider substituting so,
when x is -2 y should be

rewrite ⅕ in exponent notation:

by law of exponent we obtain:

simplify square:

when x is -1:

rewrite ⅕ in exponent notation:

use law of exponent which yields:

when x is 3:

by law of exponent we obtain:

simplify square which yields:

Answer:
A. f(x)= 8(2)^x
Step-by-step explanation:
hope that helped