Below is the diagram showing you how this has been set up. The figure is a trapezoid which means BC and AD are parallel. AC is a transversal of the parallel lines.
Givens
<ABC = <ACD
ABCD is a trapezoid
BC = 14
AD = 28
AC is a transversal of BC and AD
Solution
<ABC = <ACD Given
<DAC = <ACB Alternate interior angles.
ΔACB ≅ΔDAC AA
<BAC = <ADC Angles of similar triangles are equal
AC /28 = 14/AC Form a proportion from corresponding sides
AC*AC = 14 * 28 Cross multiply the proportion. Combine
AC^2 = 392 Express as prime factors.
AC^2 = 7*7*2*2*2 Take the square root of both sides
as per my point to view you can use a L.C.M so you can get the answer or you can try using a exponent way like 5by 1 as n value is 1 so it may give yoh answer
