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AysviL [449]
3 years ago
14

tres cajas contienen cuatrocientas naranjas la primera tiene veinte naranjas mas q la segunda y treinta mas q la tercera cuantas

naranjas hay en cada caja
Mathematics
1 answer:
Lemur [1.5K]3 years ago
5 0

Answer: Box3 has 120 oranges.

Box1 has 150 oranges.

Box  has 130 oranges.

Step-by-step explanation:

I will answer this in English.

The question says:

3 boxes have 400 oranges.

The first one has 20 more than the second and 30 more than the third.

So we have 3 equations:

box1 + box2 + box3 = 400

box1 = box2 + 20

box1 = box3 + 30

Now, we can take the variable box1 in the third equation and replace it on the other two.

box3 + 30 + box2 + box3 = 400

box3 + 30 = box2 + 20

Now we can isolate one of the variables in the second equation, let's isolate box2.

box2 = box3 + 30 - 20 = box3 + 10

now we can replace it in the other equation:

box3 + 30 + box2 + box3 = 400

box3 + 30 + box3 + 10 + box3 = 400

3*box3 + 40 = 400

3*box3 = 400 - 40 = 360

box3 = 360/3 = 120.

Box3 has 120 oranges.

Box1 has 120 + 30 = 150 oranges.

Box  has 150 - 20 = 130 oranges.

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And the answer is yes

because both cross products are 28.

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Step-by-step explanation:

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7 0
2 years ago
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A sample of men's heights was taken and the mean was 68.8 inches. The standard deviation is 2.8 inches. What percent of the men
jarptica [38.1K]

Answer:

87.29%

Step-by-step explanation:

Given: Mean= 68.8 inches

           Standard deviation= 2.8 inches

           

Now, finding the percent of the men in the sample were greater than 72 inches.

We know, z-score= \frac{x-mean}{standard\ deviation}

z-score= \frac{72-68.8}{2.8}

⇒ z-score= \frac{3.2}{2.8} = 1.14

∴ z-score= 1.14

Next, using normal distribution table to find percentage.

Coverting 0.8729 into percentage= 0.8729\times 100

We get the percentage as 87.29%

Hence, 87.29% of the men in the sample were greater than 72 inches.

6 0
3 years ago
Find an equation in standard form for the hyperbola with vertices at (0, ±6) and foci at (0, ±9).
Dvinal [7]
<span>For given hyperbola:
center: (0,0)
a=7 (distance from center to vertices)
a^2=49
c=9 (distance from center to vertices)
c^2=81
c^2=a^2+b^2
b^2=c^2-a^2=81-49=32
Equation of given hyperbola:


..
2: vertices (0,+/-3) foci (0,+/-6)
hyperbola has a vertical transverse axis
Its standard form of equation:  , (h,k)=(x,y) coordinates of center
For given hyperbola:
center: (0,0)
a=3 (distance from center to vertices)
a^2=9
c=6 (distance from center to vertices)
c^2=36 a^2+b^2
b^2=c^2-a^2=36-9=25
Equation of given hyperbola:
</span>
4 0
3 years ago
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