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posledela
3 years ago
5

Whats the slope for this pls help me its timed the possible answers are

Mathematics
1 answer:
bulgar [2K]3 years ago
5 0

Answer:

-7/5

Step-by-step explanation:

rise/run

Rise would be a negative seven, run would be positive 5.

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Strike441 [17]

how many cups does she have? you didn't day

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Who wants 100 points<br> you also get brainliest if you answer this question... 6+9=?
FrozenT [24]

Answer:

6+9=15

Step-by-step explanation:

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If 2 pounds of meat can serve 5 people how many to serve 13
Svetllana [295]

\bf \begin{array}{ccll} \stackrel{meat}{lbs}&people\\ \cline{1-2} 2&5\\ x&13 \end{array}\implies \cfrac{2}{x}=\cfrac{5}{13}\implies 26=5x \\\\\\ \cfrac{26}{5}=x\implies 5\frac{1}{5}=x

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4 years ago
Find the sum of the infinite geometric sequence:<br>8, 4, 2, 1, .......​
tatyana61 [14]

Answer:

<h3>Therefore the sum if the series is 15.98!</h3>

The common ratio is 1/2 or 0.5 . If you multiply the current term by the the common ratio the the output will be the next term.

8⋅1/2=4

4⋅1/2=2

2⋅1/2=1 etc ...

because the absolute value of r is less than 1 we can use the following formula.

a/1−r where a is the first term and r is the common ratio

In our problem

a=8 and r=0.5

Substitute

8/1−0.5=8/0.5=16

The sum of this infinite geometric series is 16.

Also, another formula you can use that is guaranteed to work every time, no matter what, is:

Sn=a(r^n−1/r−1)

All the variables work the same way as above, and "n" is the number of terms in the series. So, say you wanted to find the sum of the first 10 terms and were to substitute everything in:

S10=8(0.5^10−1/0.5−1)

S10=15.984375

Therefore the sum if the series is 15.98!

Step-by-step explanation:

<h2>Hope it is helpful....</h2>
7 0
3 years ago
Make y the subject of: k=y-1/y
gulaghasi [49]

Answer:

Concept: Algebraic Manipulation

  1. We want to make y the main variable. Start by moving y to over to one side or multiplying the inverse.
  2. So we have
  3. y =  \frac{1}{1 - k}
  4. Rate positively and give brainlist
3 0
3 years ago
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