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Novay_Z [31]
4 years ago
11

Multiply and simplify. 3x-3/x^2-1* (x+2)(x+1)/x-1

Mathematics
1 answer:
podryga [215]4 years ago
3 0
Hello,

If x≠1 and x≠-1 then

\dfrac{3x-3}{x^2-1}*\dfrac{(x+2)(x+1)}{x-1}=\dfrac{3(x-1)}{x-1}*\dfrac{(x+2)(x+1)}{(x-1)(x+1)}\\=\dfrac{3(x+2)}{x+1}




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