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LUCKY_DIMON [66]
3 years ago
11

What does B stand for in a right triangle?

Mathematics
2 answers:
mestny [16]3 years ago
3 0
Opposite angle in the right angle triangle
VikaD [51]3 years ago
3 0
It depends on what are your learning. Normally B stands for a number in a right triangle when trying tp find the hypotenuse 
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g100num [7]
1/3 of 81 = 81 • 1/3 = 81/3 = 27
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Mercury orbits around the sun is 87 24/25 earth days. Venus orbits the sun in 224 7/10 earth days, and Mars orbits the sun in 68
pav-90 [236]

For this case we have the following mixed numbers:

87 \frac {24} {25}\\224 \frac {7} {10}\\686 \frac {49} {50}

We convert each mixed number into decimal:

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Venus orbits: 224 \frac {7} {10} = \frac {10 * 224 + 7} {10} = \frac {2240 + 7} {10} = \frac {2247} {10} = 224.7

Mars orbits: 686 \frac {49} {50} = \frac {50 * 686 + 49} {50} = \frac {34300 + 49} {50} = \frac {34349} {50} = 686.98

Answer:

Mercury orbits: 87.96

Venus orbits: 224.7

Mars orbits: 686.98

5 0
3 years ago
Given cos(4x)+2<br><br> Find: Period, Shift, &amp; Range
Yuki888 [10]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}&#10;\\ \quad \\&#10;% function transformations for trigonometric functions&#10;\begin{array}{rllll}&#10;% left side templates&#10;f(x)=&{{  A}}sin({{  B}}x+{{  C}})+{{  D}}&#10;\\\\&#10;f(x)=&{{  A}}cos({{  B}}x+{{  C}})+{{  D}}\\\\&#10;f(x)=&{{  A}}tan({{  B}}x+{{  C}})+{{  D}}&#10;&#10;\end{array}\qquad

\bf \begin{array}{llll}&#10;% right side info&#10;\bullet \textit{ stretches or shrinks}\\&#10;\quad \textit{horizontally by amplitude } |{{  A}}|\\\\&#10;\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\\\&#10;\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\&#10;\end{array}

\bf \begin{array}{llll}&#10;&#10;&#10;\bullet \textit{vertical shift by }{{  D}}\\&#10;\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\&#10;\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\&#10;\bullet \textit{function period or frequency}\\&#10;\qquad \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\&#10;\qquad \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)&#10;\end{array}

now, with that template in mind, let's see

\bf \begin{array}{llccll}&#10;cos(&4x&+0)&+2\\&#10;&\uparrow &\uparrow &\uparrow \\&#10;&B&C&D&#10;\end{array} &#10;\\\\\\&#10;period\qquad \cfrac{2\pi }{B}\implies \cfrac{2\pi }{4}\implies \cfrac{\pi }{2}&#10;\\\\\\&#10;\textit{horizontal/phase shift}\qquad \cfrac{C}{B}\implies \cfrac{0}{4}\implies 0\impliedby none&#10;\\\\\\&#10;\textit{vertical shift}\qquad D=+2\impliedby \textit{2 units up}

now the range, how far up and down it goes on the y-axis

well, for the graph of cos(x), the range is, goes up to 1, down to -1, is all,

the midline is at 0

now, with a vertical shift of 2 upwards, it moves the midline by 2 units, used to be at 0, now is at y = 2, but the amplitude never changed, is goes up and down still one unit,

but with the midline at 2, goes up to 3 and down to 1, so the range is 3 ⩽ y ⩽ 1
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