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r-ruslan [8.4K]
3 years ago
11

Comment down below if u play rob.lox adopt me

Mathematics
2 answers:
katrin2010 [14]3 years ago
8 0
I play brookhaven and adopt me
rosijanka [135]3 years ago
4 0
I don't play adopt me but i still play XELLTIC
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GI and JL are parallel lines.<br><br> Which angles are supplementary angles?
solmaris [256]

Answer:

The answer is A.

Step-by-step explanation:

A supplementary angles are angles that when adding both sides will sum up to 180 Degrees.

<JKH and <LKH will be the correct answer because they add up tp 180 degrees.

Star Me!!!

6 0
3 years ago
HELP NOW PLZ AND I WILL LOVE YOU FOREVER
mr_godi [17]

Answer:

12/4+13=16 2+22/4=7.5

Step-by-step explanation:

you answer is the last option im 100 percent sure.

8 0
3 years ago
Please help asap with this question i will give brainliest.
HACTEHA [7]

Answer:

D

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k) = ( - \frac{1}{5}, \frac{1}{3} ) and r = \frac{1}{2}, thus

(x - (- \frac{1}{5} ))² + (y - \frac{1}{3} )² = ( \frac{1}{2} )², that is

(x + \frac{1}{5} )² + (y - \frac{1}{3} )² = \frac{1}{4} → D

7 0
3 years ago
How do you solve his with working
AlexFokin [52]
Check the picture below.

a)

so the perimeter will include "part" of the circumference of the green circle, and it will include "part" of the red encircled section, plus the endpoints where the pathway ends.

the endpoints, are just 2 meters long, as you can see 2+15+2 is 19, or the radius of the "outer radius".

let's find the circumference of the green circle, and then subtract the arc of that sector that's not part of the perimeter.

and then let's get the circumference of the red encircled section, and also subtract the arc of that sector, and then we add the endpoints and that's the perimeter.

\bf \begin{array}{cllll}&#10;\textit{circumference of a circle}\\\\ &#10;2\pi r&#10;\end{array}\qquad \qquad \qquad \qquad &#10;\begin{array}{cllll}&#10;\textit{arc's length}\\\\&#10;s=\cfrac{\theta r\pi }{180}&#10;\end{array}\\\\&#10;-------------------------------

\bf \stackrel{\stackrel{green~circle}{perimeter}}{2\pi(7.5) }~-~\stackrel{\stackrel{green~circle}{arc}}{\cfrac{(135)(7.5)\pi }{180}}~+&#10;\stackrel{\stackrel{red~section}{perimeter}}{2\pi(9.5) }~-~\stackrel{\stackrel{red~section}{arc}}{\cfrac{(135)(9.5)\pi }{180}}+\stackrel{endpoints}{2+2}&#10;\\\\\\&#10;15\pi -\cfrac{45\pi }{8}+19\pi -\cfrac{57\pi }{8}+4\implies \cfrac{85\pi }{4}+4\quad \approx \quad 70.7588438888



b)

we do about the same here as well, we get the full area of the red encircled area, and then subtract the sector with 135°, and then subtract the sector of the green circle that is 360° - 135°, or 225°, the part that wasn't included in the previous subtraction.


\bf \begin{array}{cllll}&#10;\textit{area of a circle}\\\\ &#10;\pi r^2&#10;\end{array}\qquad \qquad \qquad \qquad &#10;\begin{array}{cllll}&#10;\textit{area of a sector of a circle}\\\\&#10;s=\cfrac{\theta r^2\pi }{360}&#10;\end{array}\\\\&#10;-------------------------------

\bf \stackrel{\stackrel{red~section}{area}}{\pi(9.5^2) }~-~\stackrel{\stackrel{red~section}{sector}}{\cfrac{(135)(9.5^2)\pi }{360}}-\stackrel{\stackrel{green~circle}{sector}}{\cfrac{(225)(7.5^2)\pi }{360}}&#10;\\\\\\&#10;90.25\pi -\cfrac{1083\pi }{32}-\cfrac{1125\pi }{32}\implies \cfrac{85\pi }{4}\quad \approx\quad 66.75884

7 0
3 years ago
Does 3 times 9.99 give me 29.97?
Delvig [45]

Answer:

Yes it does.

Step-by-step explanation:

7 0
3 years ago
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