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Nitella [24]
3 years ago
14

on a typical day a food bank uses 230 potatoes.On thanksgiving Dat the food bank must triple the amount of potatoes they make .h

ow many potatoes will the food. bank need
Mathematics
2 answers:
KengaRu [80]3 years ago
8 0
They will need 690 potatoes on Thanksgiving Day
Sati [7]3 years ago
7 0
It would need to have 690 potatoes a day
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Nient and Units
Shtirlitz [24]
The answer is most likely C. Cubic meters.
5 0
3 years ago
What is the slope of the line plotted below? <br><br> A. 1<br> B. 2<br> C. -2<br> D. -1
ira [324]

Answer:

C. -2

Step-by-step explanation:

To find the slope of the line we take two points

((0,1) and (2, -3)

and use the formula for slope

m= (y2-y1)/ (x2-x1)

   = (-3-1)/(2-0)

    = -4/2

   = -2

5 0
3 years ago
Read 2 more answers
Solve for r 0.5(r+2.76)=3
11111nata11111 [884]

Answer:

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Step-by-step explanation:

8 0
3 years ago
Find the new amount of 140 fluid ounces increased by 45%
wlad13 [49]
\rm 140+ \frac{45*14\not0}{10\not0} =140+ \frac{63\not0}{1\not0} =140+63=\boxed{\rm203~ounces}
8 0
3 years ago
How do i solve for x? *you have to show work*
eduard
1) Factor the equation first:

2e^{2x} + 4xe^{2x} = 0
e^{2x}(2 + 4x) = 0

So either e^{2x} = 0 or 2 + 4x = 0. But e^{2x} = 0 can never equal 0! So, we only need to solve for the second equation:

2 + 4x = 0
\bf x = {-\frac{1}{2}}

2) First, single out the term with the exponent:

2 + 3(4^{2x - 1}) = 43
3(4^{2x - 1}) = 41
4^{2x - 1} = \frac{41}{3}

Now, taking the log base 4 of each side gives us

2x - 1 = \log_4 \frac{41}{3}

and we can now solve for x:

2x - 1 = \log_4 \frac{41}{3}
2x = 1 + \log_4 \frac{41}{3}
2x = \log_4 4 + \log_4 \frac{41}{3}
2x = \log_4 \frac{164}{3}
x = \frac{1}{2} \log_4 \frac{164}{3}
x = \log_4 \sqrt \frac{164}{3}
\bf x = \log_4 2 \sqrt \frac{41}{3}
8 0
3 years ago
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