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Neporo4naja [7]

4 years ago

6

A children's roller coaster is limited to riders whose height is at least 30 inches and at most 48 inches. Write two inequalitie

s that represent the height h of riders for the roller coaster.

1 answer:

SVETLANKA909090 [29]4 years ago

5 0

Answer:

h≤48 h≥30

Step-by-step explanation:

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A plane flew 3,100 kilometers at a speed of 775 kilometers per hour how many hours was the flight?

Tom [10]

3100 divided by 775 equal 4 hours

4 0

3 years ago

in the figure below trianglePQM and triangleQRP are right triangles. the measure of lineQM is 6 and the measure of lineQP is 8.

Kipish [7]

Answer:

Option 4 is correct. The length of PR is 6.4 units.

Step-by-step explanation:

From the given figure it is noticed that the triangle PQR and triangle MQR.

Let the length of PR be x.

Pythagoras formula

$hypotenuse^2=base^2+perpendicular^2$

Use pythagoras formula for triangle PQM.

$PM^2=QM^2+PQ^2$

$PM^2=(6)^2+(8)^2$

$PM^2=36+64$

$PM^2=100$

$PM=10$

The value of PM is 10. The length of PR is x, so the length of MR is (10-x).

Use pythagoras formula for triangle PQR.

$PQ^2=QR^2+PR^2$

$(8)^2=QR^2+x^2$

$64-x^2=QR^2$ .....(1)

Use pythagoras formula for triangle MQR.

$MQ^2=QR^2+MR^2$

$(6)^2=QR^2+(10-x)^2$

$36=QR^2+x^2-20x+100$

$36-x^2+20x-100=QR^2$ .... (2)

From equation (1) and (2) we get

$36-x^2+20x-100=64-x^2$

$20x-64=64$

$20x=128$

$x=6.4$

Therefore length of PR is 6.4 units and option 4 is correct.

3 0

3 years ago

Easy one - giving brainly if correct - show work.

OverLord2011 [107]

Answer:

$9.68 per Hour, $11.72 per Hour.

Step-by-step explanation:

<u>What</u> <u>you</u> <u>thought</u> <u>of..</u>

10% of original pay wage = $0.80

Sofia's Pay Wage will be incremented by 10% of $8 every 6 Months.

Function:

Sofia's Pay Wage = <em>e</em>

Original Pay Wage = <em>o</em>

Increment = <em>i</em>

6 Months = <em>t</em>

<em />

<em>e</em> = <em>o</em> + <em>ti</em>

1 Year = 12 Months

$8 + ($0.80 x 2) = $9.60

In 1 Year, Sofia's Pay Wage will be $9.60 per Hour

$8 + ($0.80 x 4) = $11.20

In 2 Years, Sofia's Pay Wage will be $11.20 per Hour

<u>What</u> <u>I</u> <u>Thought</u> <u>Of..</u>

Sofia's Pay Wage will be incremented by 10% every 6 Months.

Function:

Sofia's Pay Wage = <em>e</em>

Original Pay Wage = <em>o</em>

Increment = <em>i</em>

6 Months = <em>t</em>

<em />

<em>e</em> = <em>o</em> + <em>t(ei)</em>

1 Year = 12 Months

($8 + {10% of Sofia's Pay Wage}) = $8.80

($8.80 + {10% of Sofia's Pay Wage}) = $9.68

In 1 Year, Sofia's Pay Wage will be $9.68 per Hour

($9.68 + {10% of Sofia's Pay Wage}) = $10.65

($10.65 + {10% of Sofia's Pay Wage}) = $11.72

In 2 Years, Sofia's Pay Wage will be $11.72 per Hour

<u>Brainly?</u> (I spent a while on this)

4 0

3 years ago

Based on an indication that mean daily car rental rates may be higher for Boston than for Dallas, a survey of eight car rental c

Elina [12.6K]

Answer:

$t=\frac{(47 -44)-(0)}{3\sqrt{\frac{1}{8}+\frac{1}{9}}}=2.058$

The degrees of freedom are:

$df=8+9-2=15$

And the p value would be:

$p_v =P(t_{15}>2.058) =0.0287$

Since we have a p value lower than the significance level given of 0.05 we can reject the null hypothesis and we can conclude that the true mean for car rental rates in Boston are signiﬁcantly higher than those in Dallas

Step-by-step explanation:

Data given

$n_1 =8$ represent the sample size for group Boston

$n_2 =9$ represent the sample size for group Dallas

$\bar X_1 =47$ represent the sample mean for the group Boston

$\bar X_2 =44$ represent the sample mean for the group Dallas

$s_1=3$ represent the sample standard deviation for group Boston

$s_2=3$ represent the sample standard deviation for group Dallas

We can assume that we have independent samples from two normal distributions with equal variances and that is:

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

Let the subindex 1 for Boston and 2 for Dallas we want to check the following hypothesis:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

The statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

Where t follows a t student distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

Replacing we got:

$\S^2_p =\frac{(8-1)(3)^2 +(9 -1)(3)^2}{8 +9 -2}=9$

And the deviation would be just the square root of the variance:

$S_p=3$

The statitsic would be:

$t=\frac{(47 -44)-(0)}{3\sqrt{\frac{1}{8}+\frac{1}{9}}}=2.058$

The degrees of freedom are:

$df=8+9-2=15$

And the p value would be:

$p_v =P(t_{15}>2.058) =0.0287$

Since we have a p value lower than the significance level given of 0.05 we can reject the null hypothesis and we can conclude that the true mean for car rental rates in Boston are signiﬁcantly higher than those in Dallas

5 0

4 years ago

Let p=x^2+6. Which equation is equivalent to (x^2 + 6)^2 - 21 = 4x^2 + 24 in terms of p?

fenix001 [56]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers