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Tresset [83]
4 years ago
6

F(−2)=6 and f(0)=−4.

Mathematics
1 answer:
ra1l [238]4 years ago
3 0

Answer:

Step-by-step explanation:

i cant give you the answear because it doesnt let me send the answear :(

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Which equation represents a linear function?
devlian [24]

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y = 9 - x

Step-by-step explanation:

y = 9 - x

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3 years ago
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At noon, the temperature in Ebonsville, Texas was 29℉. By midnight, the temperature had fallen to −10℉. What was the change in t
UkoKoshka [18]

Answer:

i believe it's 39

Step-by-step explanation:

29 -39 = -10

8 0
4 years ago
Can some help me answer this question ASAP
Maru [420]

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A

Step-by-step explanation:

v + w   //substitute values

-3i + 2 - 4i  //combine like terms

-7i +2

4 0
3 years ago
What is the probability that all the roots of x2 + bx + c = 0 are real? [0,1]?
notsponge [240]

x^2+bx+c will have real roots when the discriminant of the quadratic, \Delta=b^2-4c, is non-negative, i.e.

b^2-4c\ge0\implies b^2\ge4c

Your question about probability is currently impossible to answer without knowing exactly what the experiment is. Are you picking b,c at random from some interval? Is the choice of either distributed a certain way?

I'll assume the inclusion of "[0,1]" in your question is a suggestion that both b,c are chosen indepently of one another from [0, 1]. Let B,C denote the random variables that take on the values of b,c, respectively. I'll assume B,C are identical and follow the standard uniform distribution, i.e. they each have the same PDF and CDF as below:

f_X(x)=\begin{cases}1&\text{for }0

F_X(x)=\begin{cases}0&\text{for }x

where X is either of B,C.

Then the question is to find P(B^2\ge4C). We have

P(B^2\ge4C)=P\left(C\le\dfrac{B^2}4\right)

and we can condition the random variable C on the event of B=b by supposing

P\left(C\le\dfrac{B^2}4\right)=P\left(\left(C\le\dfrac{B^2}4\right)\land(B=b)\right)=P\left(C\le\dfrac{B^2}4\mid B=b\right)\cdot P(B=b)

then integrate over all possible values of b.

=\displaystyle\int_{-\infty}^\infty P\left(C\le\dfrac{b^2}4\right)f_B(b)\,\mathrm db

=\displaystyle\int_{-\infty}^\infty F_C\left(\dfrac{b^2}4\right)f_B(b)\,\mathrm db

=\displaystyle\int_0^1\dfrac{b^2}4\,\mathrm db=\frac1{12}

4 0
3 years ago
Select the correct answer from each drop-down menu.
r-ruslan [8.4K]

Answer:

AD = DB

AE = EC

4 0
4 years ago
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