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3 years ago

What must be common about two algebraic fractions before they can be added or subtracted?

1 answer:

4 0

The two algebraic fractions can be added or subtracted only if they have the common denominators. So when adding or subtracting algebraic fractions the first thing that must be done is to take the LCM of the denominators and convert the denominators to same expressions. Only after this step the fractions can be added or subtracted. If this step is not performed, the operations cannot be performed correctly. This concept is similar to the addition and subtraction of simple fractions.

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What is the answer for Two step equations 5n+3=18

ryzh [129]

Answer: n=3

Step-by-step explanation: 5n+3=18

18-3=15

15/5=3

7 0

3 years ago

Read 2 more answers

Please i need help :/

lozanna [386]

Answer:

Step-by-step explanation:

3 0

3 years ago

Need help please! what is the total length of a 20 mm steel coiled like a spring with a 16 turns and an outer diameter of 600 mm

Norma-Jean [14]

Answer:

L = 29,550 mm

Step-by-step explanation:

i think i've done this before.. but anyway Lets make it simple and easy.

Let A = 600mm

Let B = 300mm

Let C = 16 as number turns

Let d = 20mm

L = sqrt ((3.14 * (600 - 20))² + 300³) * 16

L = 29,550 mm

4 0

4 years ago

Y = 12 <br>2x -y = 4<br><br>What is the solution of the system?

Keith_Richards [23]

2x-12=4
put the 12 in place of y since they equal each other
2x=16
add 12 to both sides
x=8
divide both sides by 2

6 0

4 years ago

Read 2 more answers

Given: AB ∥ DC , m CB =62°, m∠DAB=104° Find: m∠DEA, m∠ADB

vodka [1.7K]

Answer:

m∠DEA = 62°

m∠ADB (arc) = 194°

Angle ∠ADB = 21°.

Step-by-step explanation:

The given information are;

$AB\left | \right |DC$ , m CB (arc) = 62°, m∠DAB (arc) = 104°

arc∠BCD = 360° - 104° = 256°

m DC (arc) = arc∠BCD - arc CB = 256° - 62° (Sum of angles)

Therefore DC (arc) = 194°

m DA ≅ m CB = 62° (Parallel lines congruent arc theorem. Arc between two parallel lines)

m∠DEA = 1/2×(arc DA + arc CB) = 1/2×(62° + 62°) =62°

m∠DEA = 62°

Arc AB = m∠DAB (arc) - m DA = 104° - 62° = 42°

m∠ADB (arc) = 360 - m∠DAB (arc) - m CB (arc) (Sum of angles around a circle or point)

∴ m∠ADB (arc) = 360 - 104 - 62 = 194°

m∠ADB (arc) = 194°

Angle ADB = subtended by arc AB = ∴1/2×arc AB

Angle ∠ADB = 42/2 = 21°.

Angle = 21°

4 0

3 years ago