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nikdorinn [45]
3 years ago
12

Consumers at each trophic level convert only 10% of the energy in their food to energy for themselves. What happens to the other

90% of the energy their food produces? Check all that apply.
It is lost as gas in the atmosphere.
It is lost as heat.
It is used in life processes.
It is passed directly to offspring.
It is released once the organism dies.
Biology
2 answers:
Sergio039 [100]3 years ago
7 0

Answer:

There are two answer for this one. They are 1.) it is lost as heat. and 2.) it is used in life processes.

Explanation:

i took the test

mote1985 [20]3 years ago
4 0

it is lost as heat and  it is used in life processes

have a great day :)

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4. Use your knowledge about the relationship between nutrients and photosynthesis to explain the trends you observed in the data
Step2247 [10]

Answer:

The trends go up in the presence of nutrients.

Explanation:

There is a great relationship between nutrients and photosynthesis because photosynthesis can't occur without without the availability of nutrients. Plants uses carbon from the atmosphere which is a nutrient whereas other nutrients such as nitrogen, phosphorus, potassium etc from the soil with the help of the roots. If these nutrients are available in the surrounding, the plant produced more food during photosynthesis because these nutrients are the food of plants so the trends go up in the presence of nutrients and lowers down in the absence or lower concentration of nutrients.

6 0
3 years ago
In an experiment, a certain colony of bacteria initially has a population of 50,000. A reading is taken every 2 hours, and at th
Iteru [2.4K]

Answer:

1) Recursive definition: p_n = (50,000)3^n

2) At the beginning of the 4th interval

Explanation:

1)

The initial population of the bacteria at time zero is

p_0 = 50,000

Here we are told that the reading is taken every two hours; we call this time interval "n", so

n=2 h

And also, after every time interval n, the number of bacteria has tripled.

This means that when n = 1,

p_1 = 3 p_0

And when n=2,

p_2 = 3 p_1 = 3(3p_0)=9 p_0

Applied recursively, we get

p_n = 3^n p_0

And substituting p0,

p_n = (50,000)3^n (1)

2)

Here we want to find at the beginning of which interval there are

p=1,350,000

bacteria.

This means that we can rewrite eq.(1) as

1,350,000=(50,000)3^n

By simplifying,

27=3^n

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8 0
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