A is the corect answer ! I hope this helped !
Answer:
WILD TYPE= 425;
TAN-BARE= 425;
TAN= 75;
BARE= 75
Explanation:
Fifteen map units apart implies that 15% of the offspring are products of recombination.
Out of 1000 offsprings, therefore 15% of 1000= 0.15 × 1000=150
150 offsprings are products of recombination.
100-15 =85%
Therefore, 85% of the offspring are parental.
So, if tan-bodied, ware-winged female was mated with wild-type male resulting in F1 phenotypically wild-type females were mated to tan-bodied, bare-winged males.
The expected number of offsprings that are tanned but have normal wings would be:
Wild type= 50% of 850
0.50 × 850 = 425
Tan-bare= 50% of 850
0.50 × 850 = 425
tan= 50% of 150
0.50×150= 75
Bare= 50% of 150
0.50×150=75
Answer:
Essential bonding's are developed in the amino acids leading to formation of DNA. During cellular interaction they also provide pathways for active transportation.
Explanation:
Hydrogen bonding causes the folding of protein thereby stabilizing their structure and formation of DNA and essential bio products. These H+ bonds holds the double helix DNA molecule which zips and unzips during the cell division leading to the formation of cells with new genetic material. Also during cellular interaction and transfer of material through a permeable membrane, there is a proton oriented gated channel that causes active transport.
Hence, hydrogen bonds and van der Waals interactions are necessary for cells
