note that gradient = 
at x = a
calculate for each pair of functions and compare gradient
(a)
= 2x and = - 1
at x = 4 : gradient = 8 and - 1 : 8 > - 1
(b)
= 2x + 3 and = - 2
at x = 2 : gradient = 7 and - 2 and 7 > - 2
(c)
= 4x + 13 and = 2
at x = - 7 : gradient = - 15 and 2 and 2 > - 15
(d)
= 6x - 5 and = 2x - 2
at x = - 1 : gradient = - 11 and - 4 and - 4 > - 11
(e)
y = √x = 
= 1/(2√x) and = 2
at x = 9 : gradient = 
and 2 and 2 >
Answer:
1) The range is found by subtracting the minimum data entry from the maximum data entry.
2) It is easy to compute.
3) It uses only two entries from the data set.
Step-by-step explanation:
We are given the following information in the question:
1) Range is difference between the highest value and the lowest value of the data.
- To find the range we first arrange the data in the increasing order and then select the highest and the lowest value of the data, Then the lowest value is subtracted from the highest value to find the range.
Option A) The range is found by subtracting the minimum data entry from the maximum data entry.
2) Advantage of range as a measure of variation.
- Since the method to calculate range of a data set is very easy, it is one of the advantages to use range as a method of variation.
Option B) It is easy to compute.
3) Disadvantage of range to use as a method of variation.
- The disadvantage of using range is that it does not measure the spread of the data set
- It only measures the spread between highest and lowest data points in data set.
Option C) It uses only two entries from the data set.
When a quadratic equation ax^2+bx+c has a double root, the discriminant,
D=b^2-4ac=0
Here
a=2,
b=b,
c=18
and
D=b^2-4ac=b^2-4*2*18=0
solve for b
b^2-144=0
=> b= ± sqrt(144)= ± 12
So in order that the given equation has double roots, the possible values of b are ± 12.
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Step-by-step explanation:
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