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MAXImum [283]
3 years ago
6

In a recent survey, 70% of the 1400 female students and 30% of the 1000 male students on campus indicated that shopping was thei

r favorite leisure activity. How many students placed shopping at the top of their list? What percent of the entire student body does this represent?
Mathematics
1 answer:
nirvana33 [79]3 years ago
6 0

1280 students

53%

This is the answer to the question

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What is the average acceleration during the time interval 0 to 10 seconds
Lynna [10]
By my calculations id say its 0.5 m/s^2. 

4 0
3 years ago
It costs $35 for a membership at a wholesale store. The monthly fee is $15 .Write an equation that represents the total costs (
Anika [276]

Answer:

y= 35+15x

Step-by-step explanation:

Given data

It costs $35 for a membership

Monthly fee is $15

Let the number of months be x

and the total cost for x months be y

Hence the expression for the cost after x months is given as:

y= 35+15x

6 0
3 years ago
X-4(3-2x) =3(3x+4) is this many soultions no solutions
taurus [48]
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4 0
3 years ago
PLZZ HELP Fill in the blank with the correct response. The slope of the graph of y = x is ___a0.
Lesechka [4]

Answer:

1

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = x ← is in slope- intercept form

with slope m = 1

6 0
3 years ago
A particle moves along the curve below. y = √ 8 + x 3 As it reaches the point ( 1 , 3 ) , the y -coordinate is increasing at a r
Dmitry [639]

Answer:

<em>The x-coordinate is changing at 10 cm/s</em>

Step-by-step explanation:

<u>Rate of Change</u>

Suppose two variables x and y are related by a given function y=f(x). If they both change with respect to a third variable (time, for instance), the rate of change of them is computed as the derivative using the chain rule:

\displaystyle \frac{dy}{dt}=\frac{dy}{dx}\cdot \frac{dx}{dt}

We have

y=\sqrt{8+x^3}

Or, equivalently

y^2=8+x^3

We need to know the rate of change of x respect to t. We'll use implicit differentiation:

\displaystyle 2y\cdot \frac{dy}{dt}=3x^2\cdot \frac{dx}{dt}

Solving for dx/dt

\displaystyle \frac{dx}{dt}=\frac{2y\cdot \frac{dy}{dt}}{3x^2}

Plugging in the values x=1, y=3, dy/dt=5

\displaystyle \frac{dx}{dt}=\frac{2(3)\cdot 5}{3\cdot 1^2}=10

The x-coordinate is changing at 10 cm/s

7 0
3 years ago
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