Quanto é: xa + xb + ta + tb? Por Favor ALGUÉM ME AJUDA preciso muito!
1 answer:
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Answer:
Step-by-step explanation:
let the original fraction be
( with denominator 1 more than numerator )
Subtracting 3 from numerator/ denominator gives
=
Given that the fraction is now equivalent to , then
=
( cross- multiply )
2(n - 3) = n - 2, distribute left side
2n - 6 = n - 2 ( subtract n from both sides )
n - 6 = - 2 ( add 6 to both sides )
n = 4
and n + 1 = 4 + 1 = 5
Thus original fraction is
Answer:
and
Step-by-step explanation:
Given a polynomial with rational coefficients, its irrational and complex roots would occur in conjugate pairs.
For example, if the roots of a polynomial are 2 + , 3 and 4 - 3i, then 2 -
, and 4 + 3i are also roots of the polynomial.
Therefore, since the given polynomial has rational coefficients and some of its roots are , and -
, then -
and
are also roots of the polynomial.