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3 years ago

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Camille had $275 in her checking account . she deposited $812 and wrote checks $75, $60, and $48. how much did she have in the a

ccount after all these transactions?

1 answer:

Elenna [48]3 years ago

3 0

She would have $904. 275 + 812= 1087. 75 + 60 + 48= 183. 1087 - 183 = 904. Check the math to make sure, I did it in my head.

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Based on the information given, it should be noted that the probability distribution for y will be:

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Answer:

the answer is d.

Step-by-step explanation:

first, you want to use the formula,

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<u>____________________</u>

original value * 100

you see that 84 is the new value and 79 would be the original value. substitute the numbers in. this is a increase since you will get a positive value.

84 - 79

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79 * 100

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You are working for a company that designs boxes, bottles and other containers. You are currently working on a design for a milk

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Volume is a measure of the <u>quantity </u>of <em>substance</em> a given <u>object</u> can contain. The required answers are:

1.1 The <u>volume</u> of each <u>milk</u> carton is 360 $cm^{3}$ .

1.2 The area of <em>cardboard</em> required to make a single <u>milk</u> carton is 332.6 $cm^{2}$ .

1.3 Each <u>carton</u> can hold 0.36 liters of <u>milk</u>.

1.4 The <em>cost</em> of filling the 200 <u>cartons</u> is R 86.40.

The <u>volume</u> of a given <u>shape</u> is the amount of <em>substance</em> that it can contain in a 3-dimensional <em>plane</em>. Examples of <u>shapes</u> with volume include cubes, cuboids, spheres, etc.

The <u>area</u> of a given <u>shape</u> is the amount of <em>space</em> that it would cover on a 2-dimensional <em>plane</em>. Examples of <u>shapes</u> to be considered when dealing with the area include triangle, square, rectangle, trapezium, etc.

The box to be considered in the question is a <u>cuboid</u>. So that;

<u>Volume</u> of <u>cuboid</u> = length x width x height

Thus,

1.1 The <u>volume</u> of each <u>milk</u> carton = length x width x height

= 6 x 6 x 10

= 360

The <u>volume</u> of each <u>milk</u> carton is 360 $cm^{3}$ .

1.2 The <em>total area</em> of<em> cardboard </em>required to make a single<u> milk</u> carton can be determined as follows:

i. <u>Area</u> of the <u>rectangular</u> surface = length x width

= 6 x 10

= 60

Total <u>area</u> of the <u>rectangular</u> surfaces = 4 x 60

= 240 $cm^{2}$

ii. <u>Area</u> of the <u>square</u> surface = side x side = s²

= 6 x 6

<u>Area</u> of the <u>square</u> surface = 36 $cm^{2}$

iii. There are four <em>semicircular</em> <u>surfaces</u>, this implies a total of 2 <u>circles</u>.

<em>Area</em> of a <u>circle</u> = $\pi r^{2}$

where r is the <u>radius</u> of the <u>circle</u>.

Total <u>area</u> of the <em>semicircular</em> surfaces = 2 $\pi r^{2}$

= 2 x $\frac{22}{7}$ x $(3)^{2}$

= 56.57

Total <u>area</u> of the <em>semicircular</em> surfaces = 56.6 $cm^{2}$

Therefore, total area of <em>cardboard</em> required = 240 + 36 + 56.6

= 332.6 $cm^{2}$

The <u>area</u> of <em>cardboard</em> required to make a single <em>milk carton</em> is 332.6 $cm^{2}$ .

1.3 Since,

1 $cm^{3}$ = 0.001 Liter

Then,

360 $cm^{3}$ = x

x = 360 x 0.001

= 0.36 Liters

Thus each<em> carton</em> can hold 0.36 liters of <u>milk</u>.

1.4 total cartons = 200

<em>Total volume</em> of <u>milk </u>required = 200 x 0.36

= 72 litres

But, 1 kiloliter costs R1 200. Thus

<em>Total volume</em> in kiloliters = $\frac{72}{1000}$

= 0.072 kiloliters

The <u>cost</u> of filling the 200 cartons = R1200 x 0.072

= R 86.40

The <u>cost</u> of filling the 200 <u>cartons</u> is R 86.40.

For more clarifications on the volume of a cuboid, visit: brainly.com/question/20463446

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2 years ago