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3 years ago

Name the segment that are skew to cd

Mathematics

2 answers:

Airida [17]3 years ago

8 0

Answer:

The correct option is C.

Step-by-step explanation:

Two line are called skew lines if they are neither parallel nor perpendicular.

The given segment is CD.

From the given figure it is clear that

$CD\parallel AB\parallel EF\parallel GH$

$CD\perp AC, CG, BD, DH$

In option A, the given segments are

AE, EF, BF, EG

EF is parallel to CD, therefore option A is incorrect.

In option B, the given segments are

FH, AE, CG, BF

CG is perpendicular to CD, therefore option B is incorrect.

In option C, the given segments are

FH, EG, AE, BF

All the segments are skew to CD because they are neither parallel not perpendicular, therefore option C is correct.

In option D, the given segments are

BF, GH, EG, AE

GH is parallel to CD, therefore option D is incorrect.

leonid [27]3 years ago

4 0

Answer: AE, EG, BF, and FH

Step-by-step explanation:

First of all, please do not spam questions.

Second of all, skew lines are lines that are neither parallel nor perpendicular.

The only four lines to do that are FH, EG, AE, and BF.

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What is the measurement of angle g?

lisov135 [29]

Answer:

The answer is 26

Step-by-step explanation:

64+ 90= 154. 180-154=26, your missing angle

5 0

3 years ago

Differentiate the equation to find the functions for <br> Velocity v= ds/dt

horrorfan [7]

Differentiation from First Principles is a formal method for determining a tangent's gradient.

<h3>What is meant by differentiation?</h3>

Finding a function's derivative is the process of differentiation. It is also the process of determining how quickly a function changes in relation to its variables.

According to the Sum rule, a sum of functions' derivatives equals the sum of those functions' derivatives. The derivative of two different functions is the difference of their derivatives, according to the Difference rule.

Differentiation from First Principles is a formal method for determining a tangent's gradient. The straight line connecting any two locations on the curve that are fairly near to one another will have a gradient that is similar to that of the tangent at those places.

s(t) = ∫vdt = ∫sin(πt)dt = (-cos(πt))/π + c

substituting the values t = 3, we get

s(-3) = (-cos(-3π))/π + c = 0

simplifying the above equation, we get

(-cos(3π))/π + c = 0

1/π + c = c

c = -1/π

Therefore, the correct answer is s(t) = (-cos(πt))/π - 1/π = (-cos(πt) - 1)/π.

The complete question is:

Given the velocity v=ds/dt and the initial position of a body moving along a coordinate line, find the body's position at time t. v=sin(pi*t), s(-3)=0

To learn more about Differentiation refer to:

brainly.com/question/954654

#SPJ13

7 0

1 year ago

A rectangular flower bed covers an area of 11.76 square feet in the garden. The width of the flower bed is 3.5 feet less than it

Degger [83]

The length and width of the garden will be obtain as follows:
let the length be x ft, the width will be (x+3.5)ft
area of the bed will be:
A=length*width
11.76=x(x+3.5)
11.76=x^2+3.5x
thus
x^2+3.5x-11.76=0
solving this by quadratic formula we get:
x=[-b+/-sqrt(b^2-4ac)]/2a
thus plugging in the values we obtain
x=[-3.5+/-sqrt(3.5^2-4(-11.76*1))]/2
x=[-3.5+/-sqrt59.29]/2
x=[-3.5+/-7.7]/2
x=4.2 or -11.2
thus the length will be x=4.2 ft and the width will be x-3.5=0.7 ft

8 0

3 years ago

I need help on this quick

Pachacha [2.7K]

Answer:

The hypotenuse to the nearest tenth is 8.1

Step-by-step explanation:

We can use the Pythagorean theorem to solve

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

Let a be the x leg and b be the y leg

a = 7 units

b= 4 units

7^2 + 4^2 = c^2

49+ 16 = c^2

65 = c^2

Take the square root of each side

sqrt(65) = sqrt(c^2)

8.062257748 =c

To the nearest tenth

8.1 =c

7 0

3 years ago

Find an equivalent expression to this: 3xy + 4x + 8 + ( -2 )

Arlecino [84]

3xy + 4x -16 ...... I hope that helps .

7 0

3 years ago