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3 years ago

Please help meeeeeeee

Mathematics

1 answer:

UNO [17]3 years ago

4 0

Answer - N=2 . Solve for n by simplifying both sides of the equation then isolating the variable.

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Can someone help me pls

KatRina [158]

Answer:

x=5

Step-by-step explanation:

x=5 hope this helps!

8 0

3 years ago

0.624 in expanded form

Tpy6a [65]

The correct answer is:

0.6 + 0.02 + 0.004

Explanation:

To write a number in expanded form, we use place value. In this number, 6 is in the tenths place; that makes its value 6(0.1) = 0.6.

2 is in the hundredths place; that makes its value 2(0.01) = 0.02.

4 is in the thousandths place; that makes its value 4(0.001) = 0.004.

Together, we get a sum of 0.6+0.02+0.004.

3 0

3 years ago

Read 2 more answers

Find the quotient of these Complex Numbers. (5-i) / (3+2i)

JulsSmile [24]

Let the given complex number

z = x + ix = $\dfrac{5-i}{3+2i}$

We have to find the standard form of complex number.

Solution:

∴ x + iy = $\dfrac{5-i}{3+2i}$

Rationalising numerator part of complex number, we get

x + iy = $\dfrac{5-i}{3+2i}\times \dfrac{3-2i}{3-2i}$

⇒ x + iy = $\dfrac{(5-i)(3-2i)}{3^2-(2i)^2}$

Using the algebraic identity:

(a + b)(a - b) = $a^{2}$ - $b^{2}$

⇒ x + iy = $\dfrac{15-10i-3i+2i^2}{9-4i^2}$

⇒ x + iy = $\dfrac{15-13i+2(-1)}{9-4(-1)}$ [ ∵ $i^{2} =-1$ ]

⇒ x + iy = $\dfrac{15-2-13i}{9+4}$

⇒ x + iy = $\dfrac{13-13i}{13}$

⇒ x + iy = $\dfrac{13(1-i)}{13}$

⇒ x + iy = 1 - i

Thus, the given complex number in standard form as "1 - i".

5 0

3 years ago

13 and 14 go together

Nitella [24]

Yes it does go together

3 0

3 years ago

What is the area of this figure? ____ units²

skad [1K]

To solve the problem we could separate the figure into three parts. First figure is a triangle, second figure is a rectangle, third figure is a triangle. See image attached.

Solve each area of the figures
First figure, a triangle that have 7 units long of the base, and 2 units long of the height.
a = 1/2 × b × h
a = 1/2 × 7 × 2
a = 14/2
a = 7
The area of the first figure is 7 units²

Second figure is a rectangle, the length of the rectangle is 7 units, the width of the rectangle is 4 units.
a = l × w
a = 7 × 4
a = 28
The area of the second figure is 28 units²

Third figure is a triangle, the base is 7 units long and the height is 2 units long.
a = 1/2 × b × h
a = 1/2 × 7 × 2
a = 14/2
a = 7
The area of the third figure is 7 units²

The area of the three figures
area = first figure area + second figure area + third figure area
area = 7 + 28 + 7
area = 42
The total area of the figures is 42 units²

5 0

3 years ago