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lina2011 [118]
3 years ago
8

Combining like term 6k+7k

Mathematics
1 answer:
Nadya [2.5K]3 years ago
8 0
13k is the answer :)
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A semicircular pit has a diameter of 90 feet. Find the area of the pit to the nearest tenth of a foot.
Tom [10]

Answer:

3181 ft²

Step-by-step explanation:

area of the pit = {πD²/4}/2

where dia. = 90 feet

<u>plugin values into the formula:</u>

area of the pit = {π (90)²/4)/2

                        = 3181 ft²

7 0
3 years ago
What is the value of 12⁰?​
MatroZZZ [7]

Heyo! ;D

So, I think I may of heard about this topic in the past...are you working with degrees of circles? Plane angles? If so, you can use this formula to find your answer:

12° × \pi ÷ 180 = <u>0.2094(rad)</u>

I'm not entirely sure, however I hope this somewhat helped! If so, please lmk! Tysm and good luck!

8 0
3 years ago
Read 2 more answers
(x-2)/6 = (3x-2)/5. What is the value of x?
tatiyna
(x-2)/6 = (3x-2)/5
(x-2)*5 = (3x-2)*6

5х-10=18х-12
13х=2
х=2/13
7 0
3 years ago
Read 2 more answers
HELP PLS FIRST OONE TO ANSWER GETS BRAINLISDT
xeze [42]

Answer:

use lcm

Step-by-step explanation:

that will help

5 0
3 years ago
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Find the volumes of the solids generated by revolving the regions bounded by the graphs of the equations about the given lines.
Nina [5.8K]

Answer:

81π for the x axis.

Step-by-step explanation:

STEP ONE: Determine the intersection.

we are given from the question that y = x^2 and y = 6x − x^2. Therefore if y = x^2, then we will have;

x^2 = 6x - x^2  ---------------------------------------------------------------------------------[1].

Solving and factorizing the equation [1] above give us x = 0 and x = 3 (that is x[6 -2x] = 0 ). Therefore, the point of intersection = (0,0) and (3,9).

<u>STEP TWO</u><em>: </em>Determine the value for the cross sectional area.

The cross sectional area= [6x - x^2]π - [x2]^2 π. --------------[2].

The cross sectional area = -12 π[x -3]x^2.

<u>STEP THREE:</u> integrate the cross sectional area taking x =3 and x =0 as the upper and lower integration limits or boundaries with respect to dx to determine the vome in the x axis.

<h3>volume =∫-12 π[x -3]x^2 dx.</h3><h3 /><h3>volume = -12 π[ (3)^4/4 - (3)^3 ] = 81π.</h3>

volume, v with respect to the x axis = 81π

8 0
3 years ago
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