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Molodets [167]
4 years ago
9

Jan won 51.9% of the votes in the race for school secretary. She received 415 votes. About how many students are in the school?

Mathematics
1 answer:
slava [35]4 years ago
7 0
Mental way:
415 / 51.9 * 100 = 800 students in the school.

detailed way:
x is the amount of students in the school.
51.9% * x = 415
(divide both sides by 51.9% (or 0.519))
x = 800 students
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There are many numbers that divide 109 with a remainder of 4. List all two-digit numbers that have that property.
Paladinen [302]

Answer:

3 Numbers: 15, 21, 35

Step-by-step explanation:

We want number that divide 109 with a remainder of 4.

Thus, it can divide of 109 - 4 = 105

Factors of 105 = 3, 5, 7

Thus for getting two digit number it must be Multiple of any two factors of 105.

i.e. 15, 21 and 35

Hence there are only 3 numbers that divide 109 with a remainder of 4.

7 0
3 years ago
What is 20 divided by 10 plus 50
Deffense [45]

Answer:

20/10 + 50=52

Step-by-step explanation:

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3 years ago
Given here are a set of sample data: 12.0, 18.3, 29.6, 14.3, and 27.8. the sample standard deviation for this data is equal to _
disa [49]
The answer is 7.9306

Using the formula in the attached:
Where: xi = sample value; μ = sample mean; n = sample size

1.) Calculate the mean first:
μ = 12.0 + 18.3 + 29.6 + 14.3 + 27.8 / 5
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μ = 20.4

2.) Using the mean, calculate (xi - μ)² for each value:
(12.0 - 20.4)² = 70.56
(18.3 - 20.4)² = 4.41
(29.6 - 20.4)² = 84.64
(14.3 - 20.4)² = 37.21
(27.8 - 20.4)² = 54.76

3.) Sum the squared differences and divide by n - 1.
μ = 70.56 + 4.41 + 84.64 + 37.21 + 54.76
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μ = 62.895 (this is now called sample variance)

4.) Get the square root of the sample variance:
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3 0
3 years ago
The course grade in a statistics class is the average of the scores on five examinations. Suppose that a student's scores on the
nadya68 [22]

Answer:

84 is the highest possible course average

Step-by-step explanation:

Total number of examinations = 5

Average = sum of scores in each examination/total number of examinations

Let the score for the last examination be x.

Average = (66+78+94+83+x)/5 = y

5y = 321+x

x = 5y -321

If y = 6, x = 5×6 -321 =-291.the student cannot score -291

If y = 80, x = 5×80 -321 =79.he can still score higher

If If y = 84, x = 5×84 -321 =99.This would be the highest possible course average after the last examination.

If y= 100

The average cannot be 100 as student cannot score 179(maximum score is 100)

8 0
3 years ago
Help me answer the image below
AfilCa [17]

Answer:

8

Step-by-step explanation:

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