For the first drawing, there are 30 tickets altogether, and Jason
has 10 of them. The probability that one of his tickets will win is
10 / 30 .
For the second drawing, there are 29 tickets altogether, and Jason
has 9 of them. The probability that one of his tickets will win is
9 / 29 .
For the third drawing, there are 28 tickets altogether, and Jason
has 8 of them. The probability that one of his tickets will win is
8 / 28 .
The probability that all three of these things will happen is
(10/30) x (9/29) x (8/28) = 720 / 24,360
= 6 / 203 = 2.96 percent (rounded)
Answer:
60
Step-by-step explanation:
m(ADB) + m(BDC) = 90°
(3x+9) + (2x -4) = 90°
5x + 5 = 90°
5x = 85
5x/5 = 85/5
x = 17
m(ADB) = 3x + 9
3.17 + 9 = 51 + 9 = 60
Hope this helps ^-^
Answer: The second circle
Step-by-step explanation: I got a 100
Answer:
80x+8y=232
Step-by-step explanation:
80 times however many days worked plus 8 times however many video games sold on Thursday
