Answer:
Step-by-step explanation:hi
Answer:
![P=\frac{2n!}{m!*(2n-m)!}*0.5^{2n}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B2n%21%7D%7Bm%21%2A%282n-m%29%21%7D%2A0.5%5E%7B2n%7D)
Step-by-step explanation:
In a coin toss the probability of tossing a head is 0.5 (50% head/50% tails)
If n is the number of rounds and 2n the number of coins tossed (one for each player), the probability of having m heads tossed is:
![R=\frac{2n!}{m!*(2n-m)!}](https://tex.z-dn.net/?f=R%3D%5Cfrac%7B2n%21%7D%7Bm%21%2A%282n-m%29%21%7D)
R is the number of cases (combination of coins tossed) that gives a m number of heads. Each case has a probability of
so:
![P=\frac{2n!}{m!*(2n-m)!}*0.5^{2n}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B2n%21%7D%7Bm%21%2A%282n-m%29%21%7D%2A0.5%5E%7B2n%7D)
<u>For example, to toss 4 heads in 5 rounds: </u>
![P=\frac{10!}{4!*(10-4)!}*0.5^{10}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B10%21%7D%7B4%21%2A%2810-4%29%21%7D%2A0.5%5E%7B10%7D)
![P=\frac{10*9*8*7*6!}{4!*6!}*0.5^{10}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B10%2A9%2A8%2A7%2A6%21%7D%7B4%21%2A6%21%7D%2A0.5%5E%7B10%7D)
![P=\frac{10*9*8*7}{4!}*0.5^{10}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B10%2A9%2A8%2A7%7D%7B4%21%7D%2A0.5%5E%7B10%7D)
![P=\frac{10*9*8*7}{4!}*0.5^{10}=0.205](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B10%2A9%2A8%2A7%7D%7B4%21%7D%2A0.5%5E%7B10%7D%3D0.205)
No solution<span> would mean that there is </span>no<span> answer to the equation. It is impossible for the equation to be true </span>no<span> matter what value we assign to the variable. Infinite</span>solutions<span> would mean that any value for the variable would make the equation true.</span>No Solution<span> Equations.
</span>In other words, it "discriminates" between the possible solutions<span>. The discriminant is the expression found under the square root part of the quadratic formula (that is, . The value of tells how many </span>solutions<span>, roots, or x-intercepts the quadratic equation will have. If , there are two </span>real solutions<span>.</span>