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nordsb [41]
3 years ago
13

What are the solutions of the equation x^4 + 95x^2 - 500= 0? Use factoring to solve

Mathematics
1 answer:
Artist 52 [7]3 years ago
4 0
1) given x^4 + 95x^2 - 500

2) split in two factors with common factor term x^2: (x^2 + )(x^2 - )

3) find two numbers that add up 95 and their product is - 500:

=> 100*(-5) = - 500 and 100 - 5 = 95

=> (x^2 + 100)(x^2 - 5)

4) factor x^2 - 5 = (x + √5) (x - √5)

5) write the prime factors: (x^2 + 100) (x + √5) (x -√5)

6) find the solutions:

x^2 + 100 = 0 => not possible

x + √5 = 0 => x = - √5

x - √5 = 0 => x = √5


Answer: x = √5 and x = - √5
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2.5


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Read 2 more answers
Please help and show work!!
Ket [755]

Hi!

The answer should be third option.

20+4j\ge 2\left(j+20\right)

20+4j\geq 2j+40

20+4j-20\geq 2j+40-20

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Answer ---> j\geq 10

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