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otez555 [7]
2 years ago
14

46 divided by 3652.4

Mathematics
2 answers:
myrzilka [38]2 years ago
7 0
Assuming you can you use a calculator:
46/3652.4 = 0.126 or in simplified fraction form 5/397

Note: I am pretty sure middle school math does not require you to know how to simplify these equations by hand. 

If it does let me know and I can show you how.

kodGreya [7K]2 years ago
6 0
46/3652.4=0.01259446
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Answer: 33/3

Step-by-step explanation:

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2 years ago
Which expressions are equivalent to − f − 5 ( 2 f − 3)
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Answer:

I need the expressions

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FIND om if LO bisects
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3 years ago
Find the radius of convergence, r, of the series. ? n2xn 7 · 14 · 21 · ? · (7n) n = 1
defon
I'm guessing the series is supposed to be

\displaystyle\sum_{n=1}^\infty\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}

By the ratio test, the series converges if the following limit is less than 1.

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7\cdot14\cdot21\cdot\cdots\cdot(7n)\cdot(7(n+1))}}{\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}}\right|

The first n terms in the numerator's denominator cancel with the denominator's denominator:

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7(n+1)}}{n^2x^n}\right|

|x^n| also cancels out and the remaining factor of |x| can be pulled out of the limit (as it doesn't depend on n).

\displaystyle|x|\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2}{7(n+1)}}{n^2}\right|=|x|\lim_{n\to\infty}\frac{|n+1|}{7n^2}=0

which means the series converges everywhere (independently of x), and so the radius of convergence is infinite.
3 0
3 years ago
Help with this please
saul85 [17]
7/8 because you subtract them both by either turning them into decimals and subtracting and the
8 0
3 years ago
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